Can Volume and Linear Charge Densities Be Interchanged in Calculations?

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SUMMARY

This discussion centers on the interchangeability of volume charge density (ρ), linear charge density (λ), and surface charge density in electrostatics calculations. The user questions whether the equation r(enclosed) = λh can be modified to r(enclosed) = ρh, and seeks clarification on the application of Gauss's law with respect to a cylindrical Gaussian surface. It is established that while ρ and λ represent different physical quantities, they can be related under specific conditions, and that the electric field (E) inside a Gaussian surface can be equated to the electric field of the entire cylinder when the charge distribution is uniform.

PREREQUISITES
  • Understanding of electrostatics concepts, including charge densities.
  • Familiarity with Gauss's law and its applications.
  • Knowledge of cylindrical coordinate systems in physics.
  • Basic grasp of electric fields and their calculations.
NEXT STEPS
  • Study the relationship between different charge densities, focusing on volume, linear, and surface charge densities.
  • Learn about the applications of Gauss's law in various geometries, particularly cylindrical symmetry.
  • Explore the derivation and implications of electric fields in uniform charge distributions.
  • Review examples of Gaussian surfaces and their role in simplifying electric field calculations.
USEFUL FOR

Students of physics, particularly those studying electromagnetism, educators teaching electrostatics, and professionals involved in electrical engineering or related fields.

MtHaleyGirl
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OK, I may be out of my league here so feel free to let me know (in a nice way please) but conceptually & every other way I can come up with, I am trying to put together volume charge density, linear charge density and surface charge density ... for example in my text it says that in terms of a cylinder r(enclosed)=λh where λ is linear charge density and r is the radius of a cylinder - can I interchange ρ (for volume charge density) and λ such that r(enclosed) = ρh? - AND if I have a uniform charge distribution and I use a cylindrical gaussian surface enclosed in a larger cylinder (r for the gauss. cyl. < R -- the whole cylinder) does E(enclosed in the gauss. cyl.) = E as in the whole cylinder? Thats what Gauss's law is saying?? right?? and is q (enclosed) the same as Q(total)? ---- Thanks for any help - trying not to be a physics flunky ---- :shy:
 
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