Can we have a proton and an antiproton in the 1^S_0 atomic orbital

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SUMMARY

The discussion clarifies the interpretation of spectroscopic notation in quantum mechanics, specifically regarding the 1^S_0 and 3^S_0 states. The superscript "1" indicates a singlet state with total spin S=0, while the notation "S" denotes zero orbital angular momentum (L=0). The subscript "0" signifies that the total angular momentum (J) is also zero. The assertion that 3^S_0 could exist is incorrect, as it implies a contradiction in the addition of angular momentum states.

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Jamiemma1995
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I have a belief from something I read on the internet that the superscript 1 means that this is a singlet state so it can only hold one particle but then say 3^S_0 is a triplet so it could hold three. Then the first state I mentioned couldn't have a particle and an antiparticle in it , but the second could . Is this correct ?
 
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Jamiemma1995 said:
I have a belief from something I read on the internet

Please give a specific reference; "something I read on the Internet" is not sufficient.
 
Your may have misinterpreted what you read on the internet. It looks like you are quoting spectroscopic notation in which the meaning of subscripts and superscripts has to do with total angular momentum not the number of particles in a given state. Specifically in 1S0, the superscript "1" is the spin multiplicity ##2S+1## which means that the total spin is ##S = 0##, the letter "S" means that the total orbital angular momentum is ##L=0## and the subscript "0" means the spin and orbital angular momenta add to give ##J=0##. I don't think 3S0 can exist because it implies that, while ##S=1## and ##L=0##, their sum is ##J=0##. When you are adding nothing to something you should always get something, even in quantum mechanics!
 

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