- #1
AATroop
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Essentially, do we know [itex]\mathbb{N}[/itex][itex]\subset[/itex][itex]{P}\mathbb{(N)}[/itex]?
A subset is a set that contains elements that are all also elements of another set. In other words, every element in the subset is also present in the larger set.
It means that every element in N is also an element of P(N), and there are elements in P(N) that are not in N. In other words, N is a proper subset of P(N).
Yes, N and P(N) can have the same elements, but they must be in different orders. For example, if N = {1, 2} and P(N) = {{1}, {2}, {1, 2}}, then N is a strict subset of P(N) because N is missing the element {1, 2} which is present in P(N).
We can prove that N is strictly a subset of P(N) by showing that every element in N is also present in P(N), and that there is at least one element in P(N) that is not in N. This can be done by listing out the elements of N and P(N) and comparing them, or by using set operations such as subset and superset symbols.
No, it is not possible for N to be a subset of P(N) without being a strict subset. This is because P(N) always contains at least one more element than N, making N a proper subset of P(N).