Can you add potentials if charge redistributes?

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SUMMARY

The discussion centers on the potential energy functions of charged conductors M and N when they are brought close together. It is established that while one might think to add the isolated potential energy functions Vm(r) and Vn(r), this approach is incorrect due to charge redistribution upon proximity. The new potentials resulting from this redistribution differ from the original potentials, leading to a non-zero electric field inside the conductor, which contradicts the assumption of static charge distribution. For a comprehensive understanding of the physics and mathematics involved, refer to Griffiths' "Introduction to Electrodynamics," specifically chapters 2 and 3.

PREREQUISITES
  • Understanding of electric potential energy functions
  • Knowledge of charge redistribution in conductors
  • Familiarity with electric fields and their implications in conductors
  • Basic concepts from Griffiths' "Introduction to Electrodynamics"
NEXT STEPS
  • Study Griffiths' "Introduction to Electrodynamics," chapters 2 and 3
  • Research the principles of superposition in electrostatics
  • Explore the mathematical derivation of electric fields in conductors
  • Investigate the implications of charge distribution on potential energy
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This discussion is beneficial for physicists, electrical engineers, and students studying electromagnetism, particularly those interested in the behavior of charged conductors and electric potential theory.

amiras
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Let say we have charged conductor M and we know its potential energy function Vm(r) when M is isolated from any charges. We also have charged conductor N with potential energy function Vn(r) when it is isolated.

Now we put objects M and N close together, the charges on their surfaces redistribute. I am interested in potential energy at every point in space, can I still add potential energy functions (Vm + Vn) to find that?

I'd like to think that it is possible to add functions like that, but I can't find a way of proving it mathematically yet. Any ideas of how to show this?
 
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No, you can't do that. When the charges redistribute, the associated potential functions change. The new potentials can be added but they will be different from the original potentials.
 
Last edited:
Could you show that mathematically or find some kind of contradiction, because I am having difficulties finding easy-calculable one.
 
If you move the charge distribution, the potentials created by those charges will change as well.
 
amiras said:
Could you show that mathematically or find some kind of contradiction, because I am having difficulties finding easy-calculable one.

The issue is not about mathematics, it's about physics. Of course if you assume the charge does not redistribute, you can use superposition. But if the charges are distributed over the surface of finite-sized conductors, that is probably a bad assumption.
 
amiras said:
Could you show that mathematically or find some kind of contradiction,
The contradiction is that if you simply add the isolated potentials you will wind up with a non-zero E field inside the conductor. This will lead to a current and therefore a redistribution of charges.
 
The physics and the math for working with potentials and conductors can be found in Griffiths' "Introduction to Electrodynamics", chapters 2 and 3.

The explanations for each of the comments above will be found there as well.
 

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