MHB Can You Convert a Context-Free Grammar to a Deterministic One?

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The discussion centers on converting a context-free grammar into a deterministic one. The original grammar provided is I -> cdaX | cdbY, X -> XXX | d, Y -> I | X. The user attempts a conversion, proposing a new grammar structure with modifications. However, a participant points out that the proposed grammar allows strings like "cdadd," which are not permitted by the original grammar. The conversation highlights the importance of accurately preserving the language generated by the grammar during the conversion process. The need for careful consideration of the language's constraints is emphasized, as the proposed changes inadvertently broaden the language's acceptance.
evinda
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Hello! (Blush)

I have a context-free grammar,that I want to convert in a deterministic one.

This is the context-free grammar:

I -> cdaX|cdbY, X-> XXX |d , Y -> I | X

That's what I have tried:



I -> cdK , K ->aX | bY
X -> dM, M -> d M |N, N-> dN | ∅
Y ->cdK| dM

Is it right? Or have I done something wrong? (Thinking)
 
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evinda said:
Hello! (Blush)

I have a context-free grammar,that I want to convert in a deterministic one.

This is the context-free grammar:

I -> cdaX|cdbY, X-> XXX |d , Y -> I | X

That's what I have tried:



I -> cdK , K ->aX | bY
X -> dM, M -> d M |N, N-> dN | ∅
Y ->cdK| dM

Is it right? Or have I done something wrong? (Thinking)

Hi!

It is almost right. (Worried)

Is for instance [m]cdadd[/m] allowed? (Wondering)
 
I like Serena said:
Hi!

It is almost right. (Worried)

Is for instance [m]cdadd[/m] allowed? (Wondering)

Do you mean that it should be like that?

I -> cdK , K ->aX | bY
X -> dM, M -> d M | ∅
Y ->cdK| dM

?
(Thinking)
 
evinda said:
Do you mean that it should be like that?

I -> cdK , K ->aX | bY
X -> dM, M -> d M | ∅
Y ->cdK| dM

?
(Thinking)

No... my point was that the original language does not allow [m]cdadd[/m], while your languages both do. (Doh)
 

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