Can You Distinguish a Vacuum State in Different Color Laser Pulses?

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Discussion Overview

The discussion revolves around the concept of vacuum states in quantum optics, particularly in the context of laser pulses. Participants explore the implications of sending a vacuum state versus not sending any photons, the potential differences in signaling, and the experimental realizations of these concepts.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants question whether there is a physical difference between sending a vacuum state and sending no photons at all.
  • One participant suggests that the vacuum state has energy and that its propagation is not equivalent to the absence of signaling.
  • Another participant expresses skepticism about current theories being able to distinguish between sending a vacuum state and blocking a laser, suggesting it may be speculative.
  • A participant proposes the idea of a photon-number resolving detector to experimentally realize "vacuum state substitution" and questions if this would provide a distinction in the context of laser pulses of different colors.
  • There is a query about whether the vacuum state implies the vanishing of all observables, including energy and polarization, and how this might differ between laser pulses of different wavelengths.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether a vacuum state can be distinguished from the absence of photons. Multiple competing views remain regarding the implications and interpretations of vacuum states in quantum optics.

Contextual Notes

Limitations include the dependence on definitions of vacuum states and the unresolved nature of how different theories may interpret the physical implications of sending a vacuum state versus no photons.

phonon44145
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Can you send a light pulse consisting of |n=0> , e.e. vacuum state, and what is the physical difference between sending zero photons and sending no photons?
 
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What makes you think there is a difference? I'm not aware of any. You can't "not send" the vacuum, it's already there.
 
All articles about quantum information exchange talk at length about the possibility of one party (an adversary) intercepting a dim laser pulse and substituting the signal with a vacuum state. So does ""substituting a vacuum state" mean that the adversary will modify the signal and resend it, or does it mean that he just puts a reflecting mirror on the way of the pulse and shuts down the communication channel?
Am I correct to assume that since the vacuum state has energy, propagation of this state through space is not the same as the absence of any signaling?
 
I can't see that any current theory of physics can distinguish sending a vacuum state from not sending anything at all. Replacing a dim laser with a vacuum state sounds like blocking the laser to me, but maybe there is some distinction that quantum field theory can make. Perhaps someone more of an expert in QFT can say if there's something I'm overlooking, but it sounds like pretty speculative science to me.
 
Should it be possible to have a photon-number resolving detector (n'th outcome = n photons) and then to have the pulse blocked for any n not equal to zero? Would such an apparatus provide for an experimental realization of "vacuum state substitution"?

A separate question. Does the vacuum state mean the vanishing of all observables (energy, polarization) as well as phase exp(i*delta)? That is, will the admixture of |n=0> state in a red laser pulse be physically different from the same admixture of |n=0> state in a green laser pulse?
 

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