Can You Find the Greatest Value Using Only AM-GM Inequality?

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Homework Help Overview

The discussion revolves around finding the maximum value of the expression x3y4 subject to the constraint 2x + 3y = 7, with the conditions that x and y are non-negative. The problem utilizes the AM-GM inequality as a primary method of approach.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the AM-GM inequality, attempting to set up the problem by expressing the variables in terms of their coefficients. There is mention of sketching a graph to visualize the constraint and substituting variables to simplify the expression. Some participants suggest alternative methods like Lagrange multipliers and geometric programming, while others emphasize the requirement to use only the AM-GM inequality.

Discussion Status

The discussion is ongoing, with participants exploring various methods and clarifying assumptions about the constraints of the problem. There is recognition of the need to adhere to the AM-GM approach, despite the introduction of other methods. Some guidance has been offered regarding visualizing the problem and transforming it into a single-variable function.

Contextual Notes

Participants note the importance of the non-negativity constraints on x and y, which are relevant to the linear equation provided. There is also a mention of the need to remain within the confines of the AM-GM inequality for the solution.

utkarshakash
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Homework Statement


Find the greatest value of x^3y^4 if 2x+3y=7 and x>=0,y>=0

Homework Equations



The Attempt at a Solution


Let the 7 numbers be (x/3) 3 times and (y/4) 4 times
Using AM GM inequality
<br /> \dfrac{ 3.\frac{x}{3} + 4.\frac{y}{4}}{7} \geq \left[ \left( \frac{x}{3}\right)^3 . \left( \frac{y}{4}\right)^4\right]^{1/7} \\<br /> \left( \dfrac{x+y}{7} \right)^7 \times 3^3.4^4 \geq x^3y^4<br />
But I'm stuck here :(
 
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utkarshakash said:

Homework Statement


Find the greatest value of x^3y^4 if 2x+3y=7 and x>=0,y>=0

Homework Equations



The Attempt at a Solution


Let the 7 numbers be (x/3) 3 times and (y/4) 4 times
Using AM GM inequality
<br /> \dfrac{ 3.\frac{x}{3} + 4.\frac{y}{4}}{7} \geq \left[ \left( \frac{x}{3}\right)^3 . \left( \frac{y}{4}\right)^4\right]^{1/7} \\<br /> \left( \dfrac{x+y}{7} \right)^7 \times 3^3.4^4 \geq x^3y^4<br />
But I'm stuck here :(
It's not clear in your problem statement, but I believe the restriction of x ≥ 0, y ≥ 0 applies to the linear equation, 2x + 3y = 7.

Sketch a graph of the portion of this line that lies in the first quadrant. Then solve this equation for one of its variables to substitute into x3y4 to make this a function of one variable.
 
Mark44 said:
It's not clear in your problem statement, but I believe the restriction of x ≥ 0, y ≥ 0 applies to the linear equation, 2x + 3y = 7.

Sketch a graph of the portion of this line that lies in the first quadrant. Then solve this equation for one of its variables to substitute into x3y4 to make this a function of one variable.

Alternatively, you can use the Lagrange multiplier method. Or, you can recognize this as a so-called "Geometric Programming Problem" and use methods devised for those types of problems.

RGV
 
Ray Vickson said:
Alternatively, you can use the Lagrange multiplier method. Or, you can recognize this as a so-called "Geometric Programming Problem" and use methods devised for those types of problems.

RGV

Thanks. It solved my problem. Though I did not know Lagrange multiplier method but a little GOOGLing around helped me learn this method. But I'm required to solve this using only the A.M. G.M. inequality. Btw thanks for introducing this method to me. It will be really helpful in solving complicated problems.:smile:
 

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