Can you help me solve this Boolean algebra problem?

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SUMMARY

The Boolean algebra expression $$(\bar{a} + b)(b+c) + a\bar{b}$$ simplifies to $$a+b+c$$. The solution involves applying the rules of Boolean algebra, specifically the absorption law, which states that $$a + \bar{a}b = a + b$$. The user initially expanded the expression but struggled to eliminate the terms $$\bar{a}$$ and $$\bar{b}$$. The key to solving the problem lies in strategically applying Boolean identities to simplify the expression effectively.

PREREQUISITES
  • Understanding of Boolean algebra principles
  • Familiarity with Boolean identities and laws
  • Ability to manipulate logical expressions
  • Knowledge of the set B where elements are 0 or 1
NEXT STEPS
  • Study the absorption law in Boolean algebra
  • Learn about the consensus theorem in Boolean expressions
  • Practice simplifying Boolean expressions using Karnaugh maps
  • Explore applications of Boolean algebra in digital circuit design
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Students studying digital logic design, computer science majors, and anyone interested in mastering Boolean algebra for applications in electronics and computer engineering.

doktorwho
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Homework Statement


Prove that $$(\bar{a} + b)(b+c) + a\bar{b}$$ where ##a,b## can be from the set ##B\in\{0, 1\}## equals $$a+b+c$$

Homework Equations


Rules of Boolean Algebra
3. The Attempt at a Solution [/B]
My attempt:
##\bar{a}b + \bar{a}c + bb + bc + a\bar{b}##
##b(\bar{a} + 1+c) + \bar{a}c + a\bar{b}##
##b +\bar{a}c + a\bar{b}##
##b(\bar{a} + a) + \bar{a}c + a\bar{b}##
##b\bar{a} +ba + \bar{a}c + a\bar{b}##
##b\bar{a} + a + \bar{a}c##
and am stuck, can't get rid of these ##\bar{a}, \bar{b}##, could you help?
 
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doktorwho said:

Homework Statement


Prove that $$(\bar{a} + b)(b+c) + a\bar{b}$$ where ##a,b## can be from the set ##B\in\{0, 1\}## equals $$a+b+c$$

Homework Equations


Rules of Boolean Algebra
3. The Attempt at a Solution [/B]
My attempt:
##\bar{a}b + \bar{a}c + bb + bc + a\bar{b}##
##b(\bar{a} + 1+c) + \bar{a}c + a\bar{b}##
##b +\bar{a}c + a\bar{b}##
##b(\bar{a} + a) + \bar{a}c + a\bar{b}##
##b\bar{a} +ba + \bar{a}c + a\bar{b}##
##b\bar{a} + a + \bar{a}c##
and am stuck, can't get rid of these ##\bar{a}, \bar{b}##, could you help?
Try using ##a + \bar a b = a +b## a couple of times.
 
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