- #1

Abrain

- 8

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I'd like to understand why [tex] \int{\rho}dV = \frac{1}{c} \int{j^0}dV = \frac{1}{c} \int{j^i}dS_i [/tex] (the second equality), where

[tex] j^i = \rho \frac{dx^i}{dt} [/tex] is the current density 4-vector

[tex] \mathbf{j} = \rho \mathbf{v} [/tex] is the current density 3-vector

[tex] j^i = (c\rho, \mathbf{j}) [/tex]

[tex] \rho [/tex] is the charge density

Are you able to explain me this equality?

Thank you very much!

[tex] j^i = \rho \frac{dx^i}{dt} [/tex] is the current density 4-vector

[tex] \mathbf{j} = \rho \mathbf{v} [/tex] is the current density 3-vector

[tex] j^i = (c\rho, \mathbf{j}) [/tex]

[tex] \rho [/tex] is the charge density

Are you able to explain me this equality?

Thank you very much!

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