- #1

AmanWithoutAscarf

- 22

- 1

- Homework Statement
- I'm trying to figure out the exact current between the two plates of a disk with resistivity p, mass m, radius R and thickness d, falling in a uniform magnetic field that are parallel to the disk's surface and perdipencular to gravity field.

- Relevant Equations
- ##\displaystyle J=\frac{1}{\rho } .\mathbf{E}##

The original question was to find the final velocity after falling from the height ##H##

In many correct solutions to this problem, they consider the current density between the two surfaces to be ##\displaystyle J=\frac{1}{\rho } .\mathbf{E^{*}} =\frac{\mathbf{v} \times \mathbf{B}}{\rho }##

But I think there must be an internal electric field ##E_i## inside the disk, caused by the surface charge density, because the charges cannot change immediately due to resistance. So, electric current would be ##\displaystyle J=\frac{1}{\rho } .(\mathbf{v \times B-E}_{i})##

Is there anything that was mistaken?

In many correct solutions to this problem, they consider the current density between the two surfaces to be ##\displaystyle J=\frac{1}{\rho } .\mathbf{E^{*}} =\frac{\mathbf{v} \times \mathbf{B}}{\rho }##

But I think there must be an internal electric field ##E_i## inside the disk, caused by the surface charge density, because the charges cannot change immediately due to resistance. So, electric current would be ##\displaystyle J=\frac{1}{\rho } .(\mathbf{v \times B-E}_{i})##

Is there anything that was mistaken?