Can You Help Verify This Calculus Derivative Solution?

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Homework Help Overview

The discussion revolves around verifying a derivative solution in calculus, specifically focusing on the expression (x^3 - x^2) + (3x). The original poster shares their attempt at calculating the derivative and seeks feedback on their work.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the original poster's method of differentiation, noting typos and offering encouragement. Some suggest using online tools for verification, while others provide formatting tips for clarity in mathematical expressions.

Discussion Status

The conversation includes various attempts to clarify the differentiation process and improve the original poster's presentation of their work. Participants have offered constructive feedback and shared formatting techniques, contributing to a supportive learning environment.

Contextual Notes

There are indications of typos in the original poster's calculations, and some participants express concern about the clarity of the mathematical notation used. The original poster is also learning to format their questions properly, which is a part of their learning process.

Jake Minneman
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Hello, I am fourteen and "attempting" to teach myself calculus I was wondering if anyone with prior calculus knowledge would be willing to solve this derivative in order to check my answer.d
---- (x^3-x^2)+(3x)
dx
(My thought process)

d-----------------d
=--- (x^3-x^2)+---(3x)
dx---------------dx

=3x^(3-1)-2x^(3-1)+3x

=3x^2-2x+3

=3x^2-2x+3Sorry if I screwed that up.
 
Last edited:
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I wouldn't worry too much about embarrassing yourself. Everyone here had to learn this stuff at some time and probably made the same kinds of mistakes as everybody else.

You can use www.wolframalpha.com to find derivatives. Just enter "derivative of (x^3-x^2)+(3x)".
 
Thanks for the help
 
You have a couple of typos in your work, but your method and final answer are correct.
 
Jake Minneman said:
Thanks for the help
Yes I got it
 
Jake Minneman said:
Hello, I am fourteen and "attempting" to teach myself calculus I was wondering if anyone with prior calculus knowledge would be willing to solve this derivative in order to check my answer.


d
---- (x^3-x^2)+(3x)
dx
(My thought process)

d-----------------d
=--- (x^3-x^2)+---(3x)
dx---------------dx

=3x^(3-1)-2x^(3-1)+3x
In the line above, it should be
=3x^(3-1)-2x^(2[/color]-1)+3[STRIKE]x[/STRIKE]
Jake Minneman said:
=3x^2-2x+3

=3x^2-2x+3


Sorry if I screwed that up.
 
Mark44 said:
In the line above, it should be
=3x^(3-1)-2x^(2[/color]-1)+3[STRIKE]x[/STRIKE]

Thank you the typing of the question has been giving me trouble.
 
You might want to look into how to format things using LaTeX. You can click any of the lines below to see what I did.
\frac{d}{dx}(x^3 - x^2 + 3x)
=\frac{d}{dx}x^3 - \frac{d}{dx}x^2 + \frac{d}{dx}3x
=3x^{3 -1} - 2x^{2 -1} + 3x^{1 - 1}
=3x^2 - 2x + 3
 
Mark44 said:
You might want to look into how to format things using LaTeX. You can click any of the lines below to see what I did.
\frac{d}{dx}(x^3 - x^2 + 3x)
=\frac{d}{dx}x^3 - \frac{d}{dx}x^2 + \frac{d}{dx}3x
=3x^{3 -1} - 2x^{2 -1} + 3x^{1 - 1}
=3x^2 - 2x + 3

This helped tremendously
 
  • #10
Glad to hear it!

There are a few LaTeX tags that I use a lot.
Integral - [ tex] \int f(x) dx [ /tex]
Definite integral - [ tex] \int_{a}^{b} f(x) dx [ /tex]
Fraction or rational expression - [ tex] \frac{x + 2}{x^2 - 4}[ /tex]
Limit - [ tex] \lim_{x \to 0} f(x) [ /tex]

If you remove the extra spaces I added in the tex tags, the expressions above render like this:

\int f(x) dx
\int_{a}^{b} f(x) dx
\frac{x + 2}{x^2 - 4}
\lim_{x \to 0} f(x)
 
  • #11
thats sweet
 

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