Can You Identify the Scientist Behind This Formula?

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Do you know this formula??

Let's try to make a little game out of scientific formulas. The idea is that I post a scientific formula which is named after a famous scientist. The goal is to guess the scientist(s) associated with the formula.

The person who answers correctly, gets to present a new formula. Etc.

So let's start easy:

[tex]\sigma(x)\sigma(p)\geq \frac{\hbar}{2}[/tex]
 
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micromass said:
Let's try to make a little game out of scientific formulas. The idea is that I post a scientific formula which is named after a famous scientist. The goal is to guess the scientist(s) associated with the formula.

The person who answers correctly, gets to present a new formula. Etc.

So let's start easy:

[tex]\sigma(x)\sigma(p)\geq \frac{\hbar}{2}[/tex]

Heisenberg!
 


Ok, here it goes a nice (but long) one, with a nice name too:

[tex] \frac{d}{dt}P_{m\rightarrow n}(t)=2\pi |\langle n|H_{int}|m\rangle |^2 \rho(E)[/tex]
 


Would that be Fermi's Golden Rule?

Here's one that's perhaps not so famous, but has a name that makes me smile when I see it:

$$\frac {n^2 - 1}{n^2 + 2} = \frac{4 \pi}{3} N \alpha$$

Hint: it's named after two people whose names are very very similar.
 


jtbell said:
Would that be Fermi's Golden Rule?

Here's one that's perhaps not so famous, but has a name that makes me smile when I see it:

$$\frac {n^2 - 1}{n^2 + 2} = \frac{4 \pi}{3} N \alpha$$

Hint: it's named after two people whose names are very very similar.


Clausius-Mossotti?

How about this:
$$ \left\langle \alpha' j'm'|T^{(k)}_{q}|\alpha j m \right\rangle = \frac{\left\langle \alpha' j'||T^{(k)}||\alpha j \right\rangle}{\sqrt{2j'+1}}\left\langle kjqm|kjj'm'\right\rangle $$
 


Dr Transport said:
$$ \left\langle \alpha' j'm'|T^{(k)}_{q}|\alpha j m \right\rangle = \frac{\left\langle \alpha' j'||T^{(k)}||\alpha j \right\rangle}{\sqrt{2j'+1}}\left\langle kjqm|kjj'm'\right\rangle $$

Wigner-Eckart Theorem.

I recognized this as soon as I saw it, but I have been too lazy to think of my own puzzle.
 
Fatou's lemma.chi(L) = [e^(ch(L)).Todd(X)](dim(X)). (3 names)Here's a rather obscure one physics students of Paul Bamberg at Harvard in the 1960's all knew:

617-495-9560 (Bamberg's number)
 
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mathwonk said:
Wannabe: I just noticed you have to answer the previous one to get to post a question.
Oh, well in that case I have no idea what your formula is lol...Newton's 2nd law is out of the question innit :)? (I deleted my post by the way)

EDIT: is it the Hirzebruch–Riemann–Roch theorem?
 
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WannabeNewton said:
Yay! Ok mine will still be ##\xi_{[a}\nabla_{b]}\kappa = 0##

zeroth law of black hole thermodynamics

##E = -\lim_{S_{\alpha}\rightarrow \mathcal{P}}\frac{1}{8\pi}\int _{S_{\alpha}}\epsilon_{abcd}\nabla^{c}\xi^{d}##
 
PhizKid said:
##E = -\lim_{S_{\alpha}\rightarrow \mathcal{P}}\frac{1}{8\pi}\int _{S_{\alpha}}\epsilon_{abcd}\nabla^{c}\xi^{d}##

Why, that's the good ol' Bondi energy, of course!

Here's mine: ##y=mx+b##
 
AnTiFreeze3 said:
Here's mine: ##y=mx+b##
Is this the Noetherian current obtained from Lorentz transformations? Seems like it.
 
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WannabeNewton said:
Is this the Noetherian current obtained from Lorentz transformations? Seems like it.

You're getting close!