Can You Prove There Are Infinite Rationals Between Two Real Numbers?

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SUMMARY

The discussion centers on proving the existence of infinitely many rational numbers between two arbitrary real numbers, x and y, where x > y. The proof presented utilizes the concept of ε (epsilon) to establish that for any positive distance |x - y| > ε, one can find rational numbers in the interval (x, y) by choosing n from the integers greater than 1. The conclusion drawn is that there are indeed infinitely many rational numbers r satisfying x < r < y, as the choice of n can be made infinitely large.

PREREQUISITES
  • Understanding of real numbers and rational numbers
  • Familiarity with the concept of limits and ε-δ definitions
  • Basic knowledge of set theory and integers
  • Ability to manipulate inequalities and fractions
NEXT STEPS
  • Study the ε-δ definition of limits in calculus
  • Explore the density of rational numbers in real numbers
  • Learn about Cantor's diagonal argument and its implications
  • Investigate the properties of rational and irrational numbers
USEFUL FOR

Students of mathematics, particularly those studying real analysis, educators teaching calculus concepts, and anyone interested in the properties of rational and irrational numbers.

Shing
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Homework Statement


If x and y are arbitrary real numbers. x>y. prove that there exist at least one rational number r satisfying x<r<y, and hence infinitely.

The Attempt at a Solution


well, I have done my proof, but comparing to the solution offered by http://ocw.mit.edu/NR/rdonlyres/Mathematics/18-014Calculus-with-Theory-IFall2002/1C8FA521-FDCE-491B-8689-955B04A4A4A2/0/pset2solutions.pdf" (*1), I have a bit doubt about whether my proof is precise enough or not.

anyway, here it is:

x,y belong to R, x<y
let|x-y|&gt;\varepsilon
let n belongs Z, n>1
obviously,\varepsilon satisfies x&lt;x+\frac{\varepsilon}{n}&lt;y
as there exist infinite numbers for n,
therefore, infinite r satisfy x<r<y

thanks for reading =)
 
Last edited by a moderator:
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Shing said:

Homework Statement


If x and y are arbitrary real numbers. x>y. prove that there exist at least one rational number r satisfying x<r<y, and hence infinitely.


The Attempt at a Solution


well, I have done my proof, but comparing to the solution offered by http://ocw.mit.edu/NR/rdonlyres/Mathematics/18-014Calculus-with-Theory-IFall2002/1C8FA521-FDCE-491B-8689-955B04A4A4A2/0/pset2solutions.pdf" (*1), I have a bit doubt about whether my proof is precise enough or not.

anyway, here it is:

x,y belong to R, x<y
let|x-y|&gt;\varepsilon
let n belongs Z, n>1
obviously,\varepsilon satisfies x&lt;x+\frac{\varepsilon}{n}&lt;y
as there exist infinite numbers for n,
therefore, infinite r satisfy x<r<y

thanks for reading =)

If \epsilon is not a rational number, then is \epsilon/n rational?

If |x-y|&gt;\epsilon then can you find a rational number such that \epsilon is larger than this rational number? The rest of your arguments can be used provided you find this rational number.
 
Last edited by a moderator:

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