Can You Simplify this Trig Identity?

  • Thread starter Thread starter sean trom
  • Start date Start date
  • Tags Tags
    identities
Click For Summary

Homework Help Overview

The original poster attempts to show that the expression (sin(2theta) - sin(theta)) / (cos(2theta) - cos(theta) + 1) is equal to tan(theta). The problem involves trigonometric identities and simplification techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of double angle formulas and factorization as methods for simplification. Some express frustration with the process, while others seek clarification on specific steps and reasoning.

Discussion Status

There is active engagement with various participants offering insights and guidance. Some participants question the clarity of explanations and the appropriateness of providing full solutions, emphasizing the importance of guiding the original poster through the problem rather than giving direct answers.

Contextual Notes

Participants note the challenge of mental blocks in proving trigonometric identities and the need for foundational understanding in earlier concepts. There is a recognition of the forum's rules against providing complete solutions.

sean trom
Messages
5
Reaction score
0

Homework Statement


Show that (sin(2theta) - sin(theta)) / (cos(2theta) - cos(theta) + 1) = tan(theta)

sorry if this setting out is unclear but i am not familiar with how to post math symbols and such.

Homework Equations


above


The Attempt at a Solution



I have tried simplifying using double angle formulae but it seems i am going backwards instead of forwards. This is really frustrating as it seems to be quite simple but when I try to solve, i get nowhere.

Thanks.
 
Physics news on Phys.org
[tex]\frac{sin (2\theta) - sin (\theta)}{cos (2\theta) - cos (\theta) +1} = \frac{2 sin (\theta) cos (\theta) - sin (\theta)}{2 cos^{2} (\theta) - cos (\theta)} = \frac{sin (\theta)}{cos (\theta)} = tan (\theta)[/tex]
 
i can see how you got from the first to second stage (using double angle formulae), but how did you come to the 3rd stage, can you please show me smaller steps?
 
Factorisation; you will see that the numerator and denominator share a common term, [tex]2 cos(\theta) - 1[/tex]
 
Fightfish said:
Factorisation; you will see that the numerator and denominator share a common term, [tex]2 cos(\theta) - 1[/tex]

sorry if I am frustrating but i don't quite understand what you mean here. how does the [tex]2 cos^2(\theta)[/tex] get eliminated? what happens to the numerator when the [tex]sin(\theta)[/tex] gets taken away?
 
Fightfish said:
[tex]\frac{sin (2\theta) - sin (\theta)}{cos (2\theta) - cos (\theta) +1} = \frac{2 sin (\theta) cos (\theta) - sin (\theta)}{2 cos^{2} (\theta) - cos (\theta)} = \frac{sin (\theta)}{cos (\theta)} = tan (\theta)[/tex]

Fightfish, please do not give full solutions. We are here to guide, and help the OP, not to provide solutions. We can give them a push, or tell them what they should do, or blah blah blah. Giving full solutions is against the forum rules since it does not help much, and isn't beneficial to the OP at all.

Just bear this in mind though:

Give a man a fish, and he will eat for a day. Teach a man to fish, and he will eat for a lifetime. :)
 
Sorry, I was under the assumption that the major barrier in such proving questions was usually just a mental block or "lack of inspiration", and hence that it wouldn't hurt to provide the solution in this case
 
sean trom said:
sorry if I am frustrating but i don't quite understand what you mean here. how does the [tex]2 cos^2(\theta)[/tex] get eliminated? what happens to the numerator when the [tex]sin(\theta)[/tex] gets taken away?

Factorization means that you take out the common factor, like this:

ab + ac = a(b + c)

Since ab, and ac both have the factor a, so we can "pull" it out.

Another example is:

sin(x) + sin(x)cos(x) = sin(x) (1 + cos(x)), we simply pull sin(x) out.

Now, tell me, how can one factor the numerator, and denominator in your problem?

Fightfish said:
Sorry, I was under the assumption that the major barrier in such proving questions was usually just a mental block or "lack of inspiration", and hence that it wouldn't hurt to provide the solution in this case

Well, this is one of the fundamental problems, the basic ones. It'd be much better if you can guide the OP through it. He can learn more as he completes the problem on his own. He can do it, it's just that he didn't "see" the pattern. (and this is why he comes here) Or maybe he's lacking some earlier concepts. (we can give him some links, or review them for him) If it's a harder problem, you can give him a push, well.. but I don't think you need to do so in this case. And in some special cases, if it's a very hard problem, and if the OP has put much effort on the problem, but still go no where, then you can post a full solution. But this case is really really rare. :)
 
Last edited:
yep i understand now, thanks everyone.
 

Similar threads

Replies
54
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
17
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
18
Views
3K