- #36

SammyS

Staff Emeritus

Science Advisor

Homework Helper

Gold Member

- 11,926

- 1,519

You still haven't correctly stated what is wrong with this.SammyS said:Not quite right.

Details:

##\displaystyle \sqrt {\cos^2\theta + (i^2\sin\theta)}##

is wrong in a couple of ways,

BY the way, the rest of what you had was correct, That is; ##\displaystyle r=\sqrt {\cos^2\theta+\sin^2\theta}=1##

is correct.