Can You Solve These Rational Equations?

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Homework Help Overview

The discussion revolves around solving rational inequalities involving algebraic expressions. The original poster presents two inequalities to analyze: one involving a linear expression and the other a quadratic expression. Participants engage in clarifying the setup and notation of these problems.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for parentheses in the expressions to avoid ambiguity. There are attempts to clarify the original problem statements and the implications of different interpretations of the numerators. Some suggest breaking down the inequalities into cases based on the sign of expressions involved.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the inequalities and questioning the setup of the problems. There is a recognition of the need to verify the expressions and the importance of correctly identifying critical points for solving the inequalities.

Contextual Notes

There are indications of potential confusion regarding the original problem statements, particularly with the numerators of the rational expressions. Participants emphasize the importance of clarity in notation and setup, which may affect the approach to solving the inequalities.

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Without actually giving you all the details of the process for #i,

Subtract x from both sides;
Multiply both sides by (x+2);

The left-hand member can be expressed as x2+x-6.
You need to consider two cases. (x+2) positive, and (x+2) negative. Also, as you might have noticed, x cannot be -2.
 
anonymous12 said:
k) 4x - 4/ x - 1 < x^2 + 3x + 2
Need parentheses! This looks like
[tex]4x - \frac{4}{x} - 1 < x^2 + 3x + 2[/tex]
Furthermore, looking at your work, it looks like the the numerator was originally 4x + 4. So which is it? 4x - 4 or 4x + 4? Please double check the problem.
 
eumyang said:
Need parentheses! This looks like
[tex]4x - \frac{4}{x} - 1 < x^2 + 3x + 2[/tex]
Furthermore, looking at your work, it looks like the the numerator was originally 4x + 4. So which is it? 4x - 4 or 4x + 4? Please double check the problem.

Sorry, the question is (4x+4)/(x-1) < x^2 + 3x + 2 and by the way how did you write the problem as:

[tex]4x - \frac{4}{x} - 1 < x^2 + 3x + 2[/tex]
 
anonymous12 said:
Sorry, the question is (4x+4)/(x-1) < x^2 + 3x + 2 and by the way how did you write the problem as:

[tex]4x - \frac{4}{x} - 1 < x^2 + 3x + 2[/tex]

There's a button in the editing window (the last one on the 2nd row, the one that looks like the summation symbol) that allows you to type in LaTeX. You should learn it -- makes the expressions/equations/inequalities much more readable.

Anyway, I think your problem here is that you set up the sign chart too early. You have this:
[tex]\frac{(x+1)(x+2)(x-1)\text{ }(-4x-4)}{x-1} < 0[/tex]
... and the problem is that it looks like the last factor (-4x-4) is multiplied by the other 3 factors, when in fact it is added (or subtracted). And so you didn't get the correct zeros for the numerator when looking for the critical points.

What you'll need to do is take the numerator (which should be written like this):
[tex](x+1)(x+2)(x-1) - 4x - 4[/tex]
multiply out the 3 factors, combine like terms with the -4x - 4, and THEN set equal to zero. Since this will be a cubic, you'll have to try the Rational Roots test. (The 3 roots are all integers, which makes things a little easier.)
 
OMG! Thank you so much! This question was driving me crazy and thanks to you I finally solved it! :)
 

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