Can You Solve This Tricky Trigonometric Floor Function Equation?

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Discussion Overview

The discussion revolves around solving the equation involving the fractional parts of trigonometric functions and the floor function: $\{ \sin \lfloor x \rfloor \}+\{ \cos \lfloor x \rfloor \}=\{ \tan \lfloor x \rfloor \}$. Participants seek to clarify the notation and context of the problem, particularly the meaning of the fractional part and the units of measurement for $x$.

Discussion Character

  • Homework-related, Conceptual clarification

Main Points Raised

  • One participant asks for clarification on the notation used in the equation, specifically the meaning of the fractional part denoted by {.}.
  • Another participant explains that the notation $\{ x \}$ represents the fractional part of $x$, defined as $x - \lfloor x \rfloor$.
  • A question is raised regarding whether $x$ is measured in radians or degrees.
  • A subsequent reply confirms that $x$ is in radians.

Areas of Agreement / Disagreement

Participants generally agree on the definitions and context of the problem, but the main equation remains unsolved, and no consensus on solutions is reached.

Contextual Notes

Clarifications about the notation and the units of $x$ are provided, but the discussion does not resolve the mathematical aspects of the equation itself.

anemone
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Solve $\{ \sin \lfloor x \rfloor \}+\{ \cos \lfloor x \rfloor \}=\{ \tan \lfloor x \rfloor \}$ for real solution(s).
 
x in radian or degree ?
 
Hi Kali, $x$ is in radian.
 
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anemone said:
Solve $\{ \sin \lfloor x \rfloor \}+\{ \cos \lfloor x \rfloor \}=\{ \tan \lfloor x \rfloor \}$ for real solution(s).
Sorry, but I'm a bit confused. I know what the floor function does but what does the {.} do?

-Dan
 
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Sorry Dan for not being clear in my question.(Blush)

{} means the fractional part of $x$, and defined by the formula $\{ x \}=x-\lfloor x \rfloor$.

Hope this clears it up!
 

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