Can't figure this radioactive thing out

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SUMMARY

The discussion revolves around calculating the age of a 13.4756 g sample of petrified wood using its C-14 activity of 11 decays/min. The half-life of carbon-14 is established at 5730 years, and the initial concentration of C-14 in freshly cut wood is 6.5 × 1010 atoms/g. The participant expresses confusion regarding the variables in the decay formula N=N0ekt, specifically identifying N0 and N, which are critical for solving the problem.

PREREQUISITES
  • Understanding of radioactive decay concepts
  • Familiarity with the half-life of isotopes, specifically carbon-14
  • Knowledge of the exponential decay formula N=N0ekt
  • Basic arithmetic and algebra skills for calculations
NEXT STEPS
  • Study the principles of radioactive decay and half-life calculations
  • Learn how to apply the exponential decay formula N=N0ekt in practical scenarios
  • Research the significance of C-14 dating in archaeology and geology
  • Practice problems involving decay rates and age determination using C-14
USEFUL FOR

Students in chemistry or physics courses, educators teaching radioactive decay, and individuals interested in radiocarbon dating techniques.

xGessx
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I can't figure this out , I've tried and tried but I was absent the day they explained this and I have no idea at all what decays/min is or any of that. I've solved 9 problems and I'm missing 4, and one of them is similar to this one that I will try to answer once you try explain this one to me.

Thank you very much!

Homework Statement


A 13.4756 g sample of petrified wood was found in a petrified forest. The sample showed a
C-14 activity of 11 decays/min.
How long has the tree been dead? The halflife of carbon-14 is 5730 years and freshly cut
wood contains 6.5 × 10^10 atoms/g of C-14 and there are 365.25 days in a year.
Answer in units of years.


Homework Equations


N=N0ek*t i think it's this? But I have no idea on how to use this


The Attempt at a Solution


I would try if I knew where to start lol
 
Physics news on Phys.org
What is N0? What is N? Do you see them in the question?
 

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