Can't understand this integral

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Homework Help Overview

The discussion revolves around an integral presented in a physics context, specifically related to interatomic forces. Participants are examining the expression and limits of the integral, questioning the validity of the exponent and the implications of infinity in the limits of integration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to clarify why the integral results in an exponent of n-1 and what happens when limits are applied. There are questions about potential mistakes in the integral setup and the treatment of infinity in the context of integration limits.

Discussion Status

Some participants are exploring different interpretations of the integral's expression and its limits. There is a mix of agreement and disagreement regarding the correctness of the antiderivative and the handling of exponents. Guidance has been offered regarding the transformation of variables and the implications of negative exponents.

Contextual Notes

Participants are working under the constraints of a specific example from a lecture, which may contain typographical errors or unclear expressions. The discussion reflects a range of assumptions about the integral's setup and the behavior of the function as limits approach infinity.

Lavace
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http://www.ph.qmul.ac.uk/phy108/CM2005_week2_Lecture3_Interatomic%20Forces2.pdf

Take a look at page 4 example 1.

Why is it, when he performs the integral, it's n-1? What happens when he puts the limts in? Where is the infinty?
 
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Lavace said:
http://www.ph.qmul.ac.uk/phy108/CM2005_week2_Lecture3_Interatomic%20Forces2.pdf

Take a look at page 4 example 1.

Why is it, when he performs the integral, it's n-1?
First question: It looks like a mistake to me. The basic integral is
[tex]-A\int \frac{1}{x^n} dx = -A \int x^{-n} dx = \frac{-A}{-n + 1}x^{-n + 1} + C[/tex]
If you take the (-1) from A and multiply the (-n + 1) you get (n - 1). The exponent of n on the 1/r' is incorrect.

Lavace said:
What happens when he puts the limts in? Where is the infinty?
Second question. For the infinite integration limit you need to substitute a noninfinite variable in for r', and then let that variable get larger without bound.
 
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Thanks for that.

So what happens (result) when he subtracted this ever increasing value of r?

Also, how do you multiply the -1 to the power? (well I know how, but I wouldn't have thought I could do that?)
 
Actually, it is correct, because his answer is in terms of (1/r). Using your example, you have x^(-n+1). By turning x to 1/x, you introduce another negative sign on the exponent making it
x^(n-1)

Edit: That last part, that I wrote, should be (1/x)^(n-1).
 
Chrisas said:
Actually, it is correct, because his answer is in terms of (1/r). Using your example, you have x^(-n+1). By turning x to 1/x, you introduce another negative sign on the exponent making it
x^(n-1)

Edit: That last part, that I wrote, should be (1/x)^(n-1).

The final answer might be correct (I haven't finished the problem), but the expression he (she?) got for the antiderivative is incorrect for the reason I gave in my previous post. That is, unless you can convince me that my work is in error.
 
Oh..you mean the part on the second line all the way on the right side...yeah, looks like a typo on the first r' term in the denominator, should be -n+1. I was looking at the final line, which is correct.
 

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