Capacitance Calculation for Dielectric-Filled Coaxial Cable

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Yes.

E is always radial, H is always along phi (in cylindrical coordinates) so P is always along z. I meant that the magnitudes change, not the direction.
 
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rude man said:
Yes.

E is always radial, H is always along phi (in cylindrical coordinates) so P is always along z. I meant that the magnitudes change, not the direction.
Many thanks for all your help. Last question: in the first part, if we were to do as you suggest and find D first (which I think makes more sense) rather than E, then how do you know that D is radial? Do we assume that the dielectric material has a linear susceptibility and hence that the D field inside the dielectric is related to the E field in a vacuum by the relation D = εE?
 
CAF123 said:
Many thanks for all your help. Last question: in the first part, if we were to do as you suggest and find D first (which I think makes more sense) rather than E, then how do you know that D is radial? Do we assume that the dielectric material has a linear susceptibility and hence that the D field inside the dielectric is related to the E field in a vacuum by the relation D = εE?

D is actually the sum of two vectors, one of which is ε0E. The other is the so-called polarization vector P. P is associated with polarized charges only. In an isotropic medium, where a single εr can be assigned (i.e. regardless of direction), E and P point in the same direction. In an introductory course you are not likely to encounter non-isotropic dielectrics for which P can point in a different direction than E, and can depend on location and/or direction.