Capacitance Calculation for Dielectric-Filled Coaxial Cable

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SUMMARY

The discussion focuses on the capacitance calculation for a dielectric-filled coaxial cable consisting of two cylindrical shells with radii b and 3b. The inner region, between b and 2b, is filled with a dielectric material characterized by a relative permittivity ε_r, while the outer region remains vacuum. The electric displacement vector D and electric field E are derived using Gauss' Law, leading to the potential difference ΔV between the cylinders and the expression for capacitance per unit length, C = γ/ΔV. Key corrections were made regarding the integration limits and the application of ε in the calculations.

PREREQUISITES
  • Understanding of Gauss' Law in electrostatics
  • Familiarity with electric displacement vector (D) and electric field (E) relationships
  • Knowledge of capacitance concepts in cylindrical geometries
  • Basic principles of dielectric materials and their properties
NEXT STEPS
  • Study the derivation of electric fields in coaxial cables using Gauss' Law
  • Learn about the impact of dielectric materials on capacitance in cylindrical structures
  • Explore the calculation of Poynting vectors in different media
  • Investigate the effects of time-varying currents on energy flow in coaxial cables
USEFUL FOR

Electrical engineers, physics students, and professionals involved in the design and analysis of coaxial cables and dielectric materials.

  • #31
Yes.

E is always radial, H is always along phi (in cylindrical coordinates) so P is always along z. I meant that the magnitudes change, not the direction.
 
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  • #32
rude man said:
Yes.

E is always radial, H is always along phi (in cylindrical coordinates) so P is always along z. I meant that the magnitudes change, not the direction.
Many thanks for all your help. Last question: in the first part, if we were to do as you suggest and find D first (which I think makes more sense) rather than E, then how do you know that D is radial? Do we assume that the dielectric material has a linear susceptibility and hence that the D field inside the dielectric is related to the E field in a vacuum by the relation D = εE?
 
  • #33
CAF123 said:
Many thanks for all your help. Last question: in the first part, if we were to do as you suggest and find D first (which I think makes more sense) rather than E, then how do you know that D is radial? Do we assume that the dielectric material has a linear susceptibility and hence that the D field inside the dielectric is related to the E field in a vacuum by the relation D = εE?

D is actually the sum of two vectors, one of which is ε0E. The other is the so-called polarization vector P. P is associated with polarized charges only. In an isotropic medium, where a single εr can be assigned (i.e. regardless of direction), E and P point in the same direction. In an introductory course you are not likely to encounter non-isotropic dielectrics for which P can point in a different direction than E, and can depend on location and/or direction.
 

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