Capacitance Calculation for Dielectric-Filled Coaxial Cable

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Homework Help Overview

The discussion revolves around calculating the capacitance of a coaxial cable filled with a dielectric material. The cable consists of two cylindrical shells with a dielectric region between them, and participants are exploring the electric displacement vector and electric field within the different regions of the cable.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Gauss' Law to derive expressions for the electric displacement vector and electric field in the dielectric and vacuum regions. There are attempts to clarify the relationship between the electric displacement and electric field, with some questioning the dimensional correctness of the derived equations.

Discussion Status

Several participants have offered guidance on using the electric displacement vector as a primary approach, suggesting that it simplifies the analysis across the dielectric boundary. There is ongoing clarification regarding the integration limits for calculating potential differences, with some participants correcting earlier assumptions about the expressions used.

Contextual Notes

Participants note the variable nature of the dielectric radius and the implications of using different assumptions for the Gaussian surfaces in their calculations. The discussion reflects a learning process where participants are encouraged to refine their understanding of the concepts involved.

  • #31
Yes.

E is always radial, H is always along phi (in cylindrical coordinates) so P is always along z. I meant that the magnitudes change, not the direction.
 
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  • #32
rude man said:
Yes.

E is always radial, H is always along phi (in cylindrical coordinates) so P is always along z. I meant that the magnitudes change, not the direction.
Many thanks for all your help. Last question: in the first part, if we were to do as you suggest and find D first (which I think makes more sense) rather than E, then how do you know that D is radial? Do we assume that the dielectric material has a linear susceptibility and hence that the D field inside the dielectric is related to the E field in a vacuum by the relation D = εE?
 
  • #33
CAF123 said:
Many thanks for all your help. Last question: in the first part, if we were to do as you suggest and find D first (which I think makes more sense) rather than E, then how do you know that D is radial? Do we assume that the dielectric material has a linear susceptibility and hence that the D field inside the dielectric is related to the E field in a vacuum by the relation D = εE?

D is actually the sum of two vectors, one of which is ε0E. The other is the so-called polarization vector P. P is associated with polarized charges only. In an isotropic medium, where a single εr can be assigned (i.e. regardless of direction), E and P point in the same direction. In an introductory course you are not likely to encounter non-isotropic dielectrics for which P can point in a different direction than E, and can depend on location and/or direction.
 

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