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roam
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Homework Statement
An infinitely long dielectric cylinder with radius R and relative permittivity ##\epsilon_r## contains a free charge density given by:
##\rho(s)= ks## for s<R and 0 for s>R, where k is a constant.
Find the polarization P and any volume or surface polarization charge densities.
Homework Equations
##D=\epsilon_0 E+P##
##P=\epsilon_0(\epsilon_r -1)E##
##\oint D.da = Q_{fenc}##
##D=\epsilon E##
Gauss's law for E fields
##\epsilon_r = \epsilon/\epsilon_0##
##\rho = \rho_{bound} + \rho_{free}## with ##\rho_{bound}=- \nabla. P## and ##\nabla. D = \rho_{free}##
The Attempt at a Solution
Using Gauss's law we find:
##E_{in} = \frac{ks^2}{3 \epsilon_0} \hat{s}##
Then we find the electric displacement D:
##\oint D.da = D 2 \pi s L = (ks) \pi s^2 L = Q_{fenc}##
##Q_{fenc} = 2\pi k l \int^s_0 s'^2 = \frac{2}{3} \pi kls^3##
##D= \frac{ks^2}{3} \hat{s}##
Now using to find polarization I have used the E found from D instead of the E found from Gauss's law (please correct me if I am wrong):
##P=D-\epsilon_0 E = \frac{ks^2}{3}(1- \frac{1}{\epsilon_r})##
Is this the correct approach?
I believe ##\rho_{free}=0## since it is a dielectric. I'm guessing we need to have surface charges ##\sigma_{bound}=+P, \ \sigma_{bound}=-P##, but since the cylinder is infinitely long, where would be the two ends in which they are located?
And for the bound volume charge density I tried to find the gradient:
##\nabla . P = \frac{1}{s} \frac{\partial}{\partial s} (\frac{ks^3}{3} (1-\frac{1}{\epsilon_r})) = ks(1-\frac{1}{\epsilon_r})##
Is this correct? Also, shouldn't the net polarization charge per unit length be zero? How do we know (or can verify) this?
Any help is greatly appreciated.
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