- #1

phys-lexic

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**1. To make a parallel plate capacitor, you have available two flat plates of aluminum (area = 190 cm2), a sheet of paper (thickness = 0.10 mm, κ = 3.5), a sheet of glass (thickness = 2.0 mm, κ. = 7.0), and a slab of paraffin (thickness = 10.0 mm, κ = 2.0). Find each's capacitance; then enter the largest capacitance possible, of the three, in nF and the smallest in pF.**

**2. (capacitance) = ((epsilon not)x(Area)x(k)) / (d)**

**d, or distance between the capacitors, would be the thickness of the paper/glass/paraffin right?**

**3. my answers are:**

5.885E-7 farads for paper

5.885E-8 farads for glass

3.363E-9 farads for paraffin

-smallest = 3363 pF (paraffin)

-largest = 588.5 nF (paper)

when i enter the values on my webassign it says I am wrong... are the values correct and just converted wrong or am i totally off [i did converted all the given values to meters before plugging them into the equation]