- #1

Parad0x88

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## Homework Statement

An isolated charged parallel-plate capacitor with the plate separation d=2 mm and area of A=10 cm2 is initially empty. One slides a polystyrene dielectric slab with thickness equal to half the plate separation and with only half the area of the plates into the region between the plates. What is the final capacitance?

## Homework Equations

C = κ((ε

^{0}A)/d)

Since no specification is made, I assume there is air in-between, thus use K of 1.00059 (given in a table)

Since the dielectric slab is only half the area, I convert it to 5 cm2, or 0.0025 m2

## The Attempt at a Solution

(8.854e

^{-12}X 0.0025) / 0.0001m

= 2.2135e

^{-10}