# Homework Help: Capacitance of a Spherical Capacitor?

1. Mar 11, 2015

### Destroxia

1. The problem statement, all variables and given/known data

The plates of a spherical capacitor have radii 51.8 mm and 55.0 mm. (a) Calculate the capacitance. (b) What must be the plate area of a parallel-plate capacitor with the same plate separation and capacitance?

(givens)

a = 51.8 mm
b = 55.0 mm
d = 3.2 mm
ε0 = 8.85E-12

(unknown)

Part a:
Csphere = ?

Part b:
A (plate area of parallel-plate capacitor) = ?

2. Relevant equations

(Spherical Capacitor) Csphere = 4πε0 * [(a*b)/(b-a)]

(Parallel Capacitor) Cparallel = (ε0*A)/d

Csphere = Cparallel

3. The attempt at a solution

Csphere = 4π(8.85E-12[F/m]) * ((51.8[mm]*55.0[mm]*E-6)/((55.0[mm] - 51.8[mm])*E-3))

= 9.896E-11 F

= 98.86 pF

I could easily solve the second part just by plugging in this capacitance for the parallel-plate capacitor, but the program I am plugging the answer into tells me my answer is wrong. I have double checked the answer, even triple checked the answer, it seems to be coming down to some calculation error?

2. Mar 11, 2015

### AlexCdeP

I don't think you've done the calculation wrong it looks correct the way you have written it, except the units inside your equation are in meters since you have already converted to that unit. Are you out by a factor of tens/tens. If that's not the issue then I don't know what the problem is.
Just to clarify you have written for example 51.8[mm] when it should be 51.8[m].

3. Mar 11, 2015

### BvU

Hello Ryan, welcome to PF !

Clear posting ! But difficult to help: I followed your working and:

Funny. I get the 99.0 pF too. And A = 358 cm2. Not much we can do then, eh ?

4. Mar 11, 2015

### Staff: Mentor

Your capacitance value looks okay. Is your program expecting some particular units or number of significant figures?

5. Mar 11, 2015

### Staff: Mentor

It would help to know the area you got, to check that.
It might require some specific units as input?

6. Mar 11, 2015

### Destroxia

I tried your answer of 99.0 pF and it worked! I looked into it, and apparently even though the program usually takes +/- 1 digit in the 2nd significant digit, this one was to the 3rd significant digit... It appears it was my problem for not looking into the programs syntax for that particular problem.

Thank you all for your help! Stupid program mistake on my end!

7. Mar 12, 2015

### BvU

I did notice a small change in your post #1 going from = 9.896E-11 F to = 98.86 pF

(and subtly typed 99.0 to leave you room to discover the typo )