Capacitance of Axon: Calculate Farads

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SUMMARY

The capacitance of an axon can be calculated using the formula C = (ε₀ * k * A) / d, where ε₀ (permittivity of free space) is 8.85418782 × 10^-12 m^-3 kg^-1 s^4 A^2, k is the dielectric constant (5 for the axon), A is the plate area (4.70 x 10^-6 m²), and d is the thickness of the membrane (1 x 10^-8 m). This approach treats the axon as a parallel plate capacitor, allowing for the determination of its capacitance in Farads. The dielectric constant must be considered as the medium differs from free space.

PREREQUISITES
  • Understanding of parallel plate capacitor theory
  • Knowledge of dielectric constants and their significance
  • Familiarity with the concept of permittivity of free space (ε₀)
  • Basic algebra for manipulating equations
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Homework Statement



An axon is the relatively long tail-like part of a neuron, or nerve cell. The outer surface of the axon membrane (dielectric constant = 5, thickness = 1 x 10^-8 m) is charged positively, and the inner portion is charged negatively.

Thus, the membrane is a kind of capacitor. Assuming that an axon can be treated like a parallel plate capacitor with a plate area of 4.70 x 10^-6 m^2, what is its capacitance?

in Farat



Homework Equations





The Attempt at a Solution


here is the equation:
View attachment untitled.bmp

there are other numbers being used as an example. I just don't know what to use for E0 if E = V/R, and I don't have V, so how do i solve this. thanks.

 
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There is a simple formula for the capacitance of a parallel plate capacitor:

<br /> C = \frac{\epsilon_o A}{d}<br />
 
Ya thanks for the formula, but i still don't know what E0 is?
 
permittivity of free space! 8.85418782 × 10-12 m-3 kg-1 s4 A2
 
StrongForce said:
permittivity of free space! 8.85418782 × 10-12 m-3 kg-1 s4 A2

yes.. but it won't work in this case, as the medium is different than free space [di-electric constant = k = 5, here]. So the formula will be:

<br /> C = \frac{\epsilon_o kA}{d}<br />

where k [in this example] is 5.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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