Capacitance of three concentric shells

  • Thread starter Thread starter Kashmir
  • Start date Start date
  • Tags Tags
    Capacitance
AI Thread Summary
To calculate the capacitance between three concentric shells, charge Q is applied to the outer shell and -Q to the innermost shell. The potential V is determined by integrating the electric field, resulting in V=kq[1/a -1/c]. The capacitance C is then calculated as C=Q/V, and this method is confirmed to be correct as the middle shell acts as an equipotential surface, not affecting the capacitance. An alternative scenario is proposed, involving a thick concentric shell with a specific wall thickness, which could provide a more complex challenge. Overall, the approach to finding capacitance remains valid without the need for integration.
Kashmir
Messages
466
Reaction score
74
Homework Statement
A friend of mine sent me this problem about finding the capacitance.
We have three concentric shells of radius a, b, c. And we've to find the capacitance between x and y.

I need help.

Thank you
Relevant Equations
C=Q/V
IMG-20230727-WA0003.jpg


I want to calculate the capacitance of this system between the points x&y.
So suppose I give a charge Q to the outermost shell and -Q to the innermost shell. To find the capacitance C, I try to find the potential V between the outermost shell and innermost shell .
To find V ,I integrate the electric field and find it out to be V=kq[1/a -1/c] where k=1/(4 *pi*epsilon). Then I can find C =Q/V.
Is this approach correct.
 
Last edited:
Physics news on Phys.org
This approach is correct. You should get the capacitance between the outer and inner shells the usual way as if the middle shell were not there. The middle shell is affecting nothing because it is an equipotential surface at the potential that would be there if there were vacuum between the shells.

A slightly more interesting problem might be to find the capacitance if a thick concentric shell were placed in between having wall thickness, say ##d=\frac{1}{2}(c-a)## with equal vacuum gaps between conductors.
 
  • Like
Likes Kashmir and berkeman
kuruman said:
This approach is correct. You should get the capacitance between the outer and inner shells the usual way as if the middle shell were not there. The middle shell is affecting nothing because it is an equipotential surface at the potential that would be there if there were vacuum between the shells.

A slightly more interesting problem might be to find the capacitance if a thick concentric shell were placed in between having wall thickness, say ##d=\frac{1}{2}(c-a)## with equal vacuum gaps between conductors.
Thank you. I’ll try your question :)
 
You don't need to do any integration. Just write down the potential at radius a due to the two shells. You know that the potential due to the outer shell there is the same as it is at radius c.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top