Capacitor (currents, resistors, etC)

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SUMMARY

The discussion centers on the behavior of a capacitor when charged through one bulb and discharged through two bulbs. Key conclusions include that the same amount of charge flows during both charging and discharging, but the flow rate is affected by the number of bulbs in the circuit. The single bulb shines brighter due to lower resistance compared to the two bulbs in series, which results in a higher total resistance and slower charge flow. The answers provided are confirmed to be true based on the principles of electrical circuits.

PREREQUISITES
  • Understanding of basic electrical concepts such as charge, current, and resistance.
  • Familiarity with series and parallel circuits.
  • Knowledge of Ohm's Law and its application in circuit analysis.
  • Basic principles of capacitors and their charging/discharging behavior.
NEXT STEPS
  • Study the differences between series and parallel circuits in detail.
  • Learn about the impact of resistance on current flow using Ohm's Law.
  • Explore capacitor charging and discharging equations in RC circuits.
  • Investigate the role of bulbs as resistive loads in electrical circuits.
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Students studying electrical engineering, educators teaching circuit theory, and hobbyists interested in electronics and capacitor behavior.

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Homework Statement



A capacitor is charged through one bulb and then discharged through two bulbs. Mark each of the following statements true or false.

a) The same amount of charge flows during charging and discharging.
b) More charge flows through the single bulb than through the two bulbs.
c) Charge flows at a greater flow through the single bulb than through the two.
d) The single bulb shines brighter than either bulb in the two bulb circuit.
e) The total resistance of the two bulbs is greater than that of the single bulb.
f) A compass would show a larger deflection for the circuit with 1 bulb than the circuit with two.
g) The brightest bulb(s) indicate the fastest charge flow.


The Attempt at a Solution


a) I am pretty sure this is true because bulbs don't affect amount of charge, but does it affect flow rate??, and i am wondering how much charge is on the + and - ends of the capacitor... and after the discharge is all the charge back on the negative side?
b) Is it false because the same amount of charge gets through, but at a slower rate?
c)True, because the resistance is higher in two bulbs, slowing down the flow rate
d)True, because the flow rate is less than the single bulb. less resistance more brighter right?
e)True, Dont need help with this 1 :)
f) True because there is less charge per second in the wire creating less of a disturbance in the field?? i don't know why.
g)True, less resistance, faster flow = brighter

PLEASE TELL ME IF IM WRONG
 
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The answers will vary depending on whether the bulbs are in series with the capacitor, or in parallel. Can you clarify?
 
the bulbs are in a series. the 1st diagram is just

wire connecting bulb to batteries and a wire connecting the bulb to the + side of the capacitor. a wire connecting battery to capacitor on - side.

2nd diagram is
wires connecting + and - side of the capacitor with 2 bulbs in between them
 

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