# Brightness of Light Bulbs in a Circuit

1. Apr 13, 2016

### cvc121

1. The problem statement, all variables and given/known data

Given the circuit diagram (attached below), predict how unscrewing each bulb separately affects the brightness of the other two bulbs?

2. Relevant equations

N/A

3. The attempt at a solution
I predict that by unscrewing one of the bulbs, the other two will get brighter. This is because there is less resistance in the circuit overall, and more current which is distributed to the other two bulbs, making them brighter. Am I on the right track here? I am only at a basic high school level so this is the best explanation I could think of given my knowledge. Any help is very much appreciated!

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2. Apr 13, 2016

### axmls

It depends on which bulb you unscrew! Go ahead and try to figure out what would happen if you were to unscrew each of the three bulbs.

3. Apr 13, 2016

### haruspex

What does the circuit look like if you unscrew, say, the bulb on the horizontal wire, B2?

4. Apr 13, 2016

### cvc121

Would B1 and B3 be in parallel with one another?

5. Apr 13, 2016

### haruspex

Have you heard of the expression "Christmas tree lights failure"?

6. Apr 13, 2016

### cvc121

No, I have not.
Let's just say that I were to unscrew B1. Wouldn't B2 and B3 both get brighter because there is less resistance in the circuit overall? However, I am not sure if that's true because of the fact that B1 is in parallel with B2 and B3 and B2 is in series with B3.

7. Apr 13, 2016

### haruspex

Consider the voltage across B1. How is that affected by removing B1?
Have you tried drawing the circuit with B1 removed?

8. Apr 13, 2016

### cvc121

Decrease

9. Apr 13, 2016

### haruspex

Why?

10. Apr 13, 2016

### cvc121

Pardon me. I believe that voltage would not change because isn't the only thing that would change the voltage be to replace the battery with a more or less powerful one. I am becoming very confused now. I have just been exposed to this topic and it has taken me a while to understand it. Sorry if I sound really dumb.

11. Apr 13, 2016

### haruspex

Right, but I still suspect you have not understood what the circuit will look like. What do you see where the bulb used to be before removing it?

12. Apr 13, 2016

### Jon B

The Battery Voltage should change very little when connecting and removing bulbs.

Mentor note: the remainder of this post has been removed because members are not permitted to provide near-complete answers to homework.

13. Apr 14, 2016

### cvc121

Thanks so much Jon B. I would just like some clarification as to why removing B1 has a negligible effect on B2 and B3 but yet removing either B2 or B3 has a negligible effect on B1 and the other bulb is no longer lit. Does it have anything to do with how the bulbs are arranged in the circuit ? (B1 is in parallel with B2 and B3, and B2 is in series with B3?)

14. Apr 14, 2016

### haruspex

Try to answer my question in post #11

15. Apr 14, 2016

### Jon B

It has everything to do with the Battery not being effected by changes in load. Its Voltage will remain relatively constant.