Capacitor Energy and Charge Relationship

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
victorializ
Messages
20
Reaction score
0

Homework Statement



If you increase the charge on a parallel plate capacitor from 3μC to 9μC and increase the plate separation from 1mm to 3mm, the energy stored in the capacitor changes by a factor of...

Homework Equations



U = 1/2QV
or 1/2CV^2

The Attempt at a Solution



I'm not sure which equation to even use, I'm not to great when it comes to differentiating between electric field and energy of the capacitor.

I think I should probably use 1/2QV but i don't have a voltage to work with so I'm confused.
 
Last edited:
Physics news on Phys.org
Use the relation between charge Q, Voltage V, and Capacitance C to eliminate the voltage from the expression for the energy.
 
dauto said:
Use the relation between charge Q, Voltage V, and Capacitance C to eliminate the voltage from the expression for the energy.

so U =1/2 Q^2/C

i'm still not sure how i would find capacitance without using the C=Q/V and not having a voltage?
also does the distance between the plates changing not matter?
 
mfb said:
The capacitance changes if you change the distance, and you should know a formula that connects the two.

oh alright i thought that the permitivity of free space had to be used when a dielectric was present only but that works thanks!