Capacitor Energy and Charge Relationship

Click For Summary

Homework Help Overview

The discussion revolves around the relationship between charge, energy, and capacitance in a parallel plate capacitor, specifically when the charge is increased and the plate separation is altered.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore which equations are applicable for calculating the energy stored in the capacitor, with some uncertainty about differentiating between electric field and energy. Questions arise regarding the use of voltage in the calculations and how to find capacitance without it. There is also discussion about the implications of changing the distance between the plates.

Discussion Status

Some participants have suggested eliminating voltage from the energy expression using relationships between charge, voltage, and capacitance. There is ongoing exploration of how changes in plate separation affect capacitance and energy, with no clear consensus yet on the best approach.

Contextual Notes

Participants express confusion about the necessary equations and the role of voltage, as well as assumptions regarding the effects of plate separation on capacitance.

victorializ
Messages
20
Reaction score
0

Homework Statement



If you increase the charge on a parallel plate capacitor from 3μC to 9μC and increase the plate separation from 1mm to 3mm, the energy stored in the capacitor changes by a factor of...

Homework Equations



U = 1/2QV
or 1/2CV^2

The Attempt at a Solution



I'm not sure which equation to even use, I'm not to great when it comes to differentiating between electric field and energy of the capacitor.

I think I should probably use 1/2QV but i don't have a voltage to work with so I'm confused.
 
Last edited:
Physics news on Phys.org
Use the relation between charge Q, Voltage V, and Capacitance C to eliminate the voltage from the expression for the energy.
 
dauto said:
Use the relation between charge Q, Voltage V, and Capacitance C to eliminate the voltage from the expression for the energy.

so U =1/2 Q^2/C

i'm still not sure how i would find capacitance without using the C=Q/V and not having a voltage?
also does the distance between the plates changing not matter?
 
The capacitance changes if you change the distance, and you should know a formula that connects the two.
 
mfb said:
The capacitance changes if you change the distance, and you should know a formula that connects the two.

oh alright i thought that the permitivity of free space had to be used when a dielectric was present only but that works thanks!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K