Capacitor Peak Current and Voltage in an AC Circuit

[ReidMerrill]

Homework Statement

A capacitor has a peak current of 240 μA when the peak voltage at 250 kHz is 2.7 V .
Part A
What is the capacitance?

Part B
If the peak voltage is held constant, what is the peak current at 500 kHz

Homework Equations

X_c=1/wC
V_c=I_cX_c

The Attempt at a Solution

I rearranged equation 2 to solve for X_c = 2.7V/0.000240A = 11250
I then rearranged equation to to solve for C =1/wX_c = 3.56x10^-4

This is not correct. Why is this not correct and what is the proper way to go about solving it?
Thank you.

Correction: I re-did the second calculation and got 3.56x10^-10F by properly converting kHz to Hz but it's still wrong.

 

[NascentOxygen]

Hi ReidMerrill.

Did you convert kHz to radians/sec?

 

[ReidMerrill]

Hi ReidMerrill.

Did you convert kHz to radians/sec?

Oh you know what I did not. I wasn't aware I needed to. My professor did not explain this well at all.
I would just divide the frequency by 2pi, correct?EDIT: That worked. Thank you!