 #1
adangerousdriver
 3
 1
 Homework Statement:

If the voltage amplitude across an 8.50nF capacitor is equal to 12.0 V when the current amplitude through it is 3.33 mA, the frequency is closest to:
5.20 MHz
32.6 Hz
5.2 kHz
32.6 kHz
32.6 MHz
 Relevant Equations:

Capacitor Reactance: Xc = 1/(ωC)
Ohm's Law: V = IXc = I/(ωC)
Frequency: f = 2πω
By combining the formula for the reactance of a capacitor with Ohm's Law for a capacitor, I can solve for angular frequency, and divide by 2π to find frequency.
The resulting equation is:
f = I/(2π VC)
Using the given values, I end up with 5.2 kHz, instead of the correct answer of 5.2 MHz. I cannot find out where I am making a mistake that throws off my order of magnitude.
The resulting equation is:
f = I/(2π VC)
Using the given values, I end up with 5.2 kHz, instead of the correct answer of 5.2 MHz. I cannot find out where I am making a mistake that throws off my order of magnitude.