Capacitor Problem: Charge, Electric Displacement, and Current Calculations

  • Thread starter Thread starter TPDC130
  • Start date Start date
  • Tags Tags
    Capacitors
Click For Summary
SUMMARY

The discussion focuses on calculating charge, electric displacement current, and wire current for a parallel plate capacitor subjected to an electric potential of Vo*sin(wt). The charge on the plates is determined using the formula Q=CV, resulting in Q=C*Vo*sin(wt). The electric displacement current is calculated as I=(epsilon)*w*cos(wt), while the current in the wire is found to be i=C*w*cos(wt). The participant expresses concern about the simplicity of the answers and seeks clarification on the difference between displacement current and wire current.

PREREQUISITES
  • Understanding of capacitor fundamentals and capacitance (C)
  • Familiarity with electric displacement current concepts
  • Knowledge of calculus for differentiation and integration
  • Basic understanding of sinusoidal functions and their derivatives
NEXT STEPS
  • Study the concept of electric displacement current in detail
  • Explore the relationship between displacement current and conduction current
  • Learn about the applications of capacitors in AC circuits
  • Investigate the mathematical derivation of current in capacitors using \LaTeX
USEFUL FOR

Students in electrical engineering, physics enthusiasts, and anyone studying circuit theory and capacitor behavior in alternating current (AC) systems.

TPDC130
Messages
6
Reaction score
0

Homework Statement


Given an electric potential of Vo*sin(wt). This is applied to a parallel plate capacitor of area S, separation d and capacitance C. The questions are
a) What is charge Q on the plates?
b) Find the electric displacement current
c) Calculate the current in the wire.


Homework Equations


a) Q=CV
b) I=(epsilon)*d(phi)/dt
c) i=dQ/dt

The Attempt at a Solution



for part a, i got Q=CV=C*Vo*sin(wt)
for part b, i got I=(epsilon)*w*cos(wt)
for part c, i got i=C*w*cos(wt)


is this right, because i have a feeling that this is a little too easy of an answer.
why does the displacement current differ from the current in the wire?
 
Physics news on Phys.org
Rewrite that with [tex]\LaTeX[/tex] code,I think it`s easy as it can be.

It`s pain to read like that.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
19
Views
3K
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
2
Views
2K