Capacitor with sinusoidal voltage placed near a plate

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Homework Help Overview

The discussion revolves around the relationship between the current output from an electrode with a sinusoidal voltage and the amplitude of vibration in a system involving a plate. The context includes concepts from electrostatics and oscillatory motion, particularly focusing on capacitive effects and their dependence on distance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the mathematical relationships involving current, voltage, capacitance, and displacement. There are attempts to derive expressions for current based on varying parameters and to clarify the role of displacement in the system. Questions arise regarding the assumptions made about the independence of certain variables and the physical setup of the system.

Discussion Status

The discussion is ongoing, with participants providing insights and alternative perspectives on the relationship between current and displacement. Some suggest that the current may be proportional to displacement, while others question this assumption and seek clarification on the physical interpretation of the variables involved.

Contextual Notes

There is a noted complexity in the system due to the interplay between the applied voltage, the capacitance, and the displacement of the oscillator. Participants express uncertainty about the completeness of the information and the implications of their findings, indicating that further exploration is needed.

unscientific
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Homework Statement



An electrode with a varying voltage V = V0 + VACejωt is placed near a plate. The current output from the electrode is then measured. We want to find the relation between the current output and the amplitude of vibration. We can assume VAC is small relative to V0.


Homework Equations



Idea:

1. Constant charge in plate -> Constant force exerted -> separation changes -> capacitance changes
2. Apply sinusoidal voltage->phase change of force for every ∏ rad -> oscillation
3. these leads to changes in output current detected in electrode.

The Attempt at a Solution



V = V0 + VACe(jωt)
Q = CV
I = V*dC/dt + C*dV/dt
I = jCVACωejωt + V*dC/dt


C = ε0A/d
dC/dt = - (ε0A/d2) * d(d)/dt

I = jCVACωejωt + V*(ε0A/d2) * d(d)/dt

To find: d(d)/dt

F = Q2/(2ε0A)
m*dv/dt = Q2/(2ε0A)

v = Q2/(2mε0A) * t

therefore, the current is:

I = jCVACωejωt + Q3/(2ε0Am) * (1/d) * t

So the current depends both on time and inversely to displacement?
 
Last edited:
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bumpp. My supervisor believes the current is proportional to the displacement though.
 
It's application is on a torsional oscillator driven capacitively.
 
If this is a driven system then there must be some sort of torsional spring restraining element between the plates pulling them apart. Because the plates are always drawn together by the applied voltage irrespective of its polarity. What is the torsional spring constant? What is d when the torsion torque is zero?

OR: are you sure this is not just a displacement sensor? In other words, is d not the independent variable? In which case force is not a consideration.
 
rude man said:
If this is a driven system then there must be some sort of torsional spring restraining element between the plates pulling them apart. Because the plates are always drawn together by the applied voltage irrespective of its polarity. What is the torsional spring constant? What is d when the torsion torque is zero?

OR: are you sure this is not just a displacement sensor? In other words, is d not the independent variable? In which case force is not a consideration.

The plate is in fact a torsional oscillator, driven capacitively by the electrodes. So a sinusoidal voltage is applied to the electrode which attracts the oscillator at a certain frequency ω. The current depends on the capacitance, which in turn depends on the distance between the electrode and the oscillator. I want to find the relationship between the current observed and the distance between them.
 
unscientific said:
I want to find the relationship between the current observed and the distance between them.

So why are you pursuing force on the plates? As I suspected, d is the independent variable. You already did a lot of analysis & came up with (incl. sign correction)
I = jCVACωejωt - V*(ε0A/d2) * d(d)/dt

I suggest replacing d with h to avoid confusion.

So that's I = jCVacωejωt - V*(ε0A/h2) * dh/dt

Now, replacing C with ε0A/h and V with V0 + Vacejwt you get

I = jwε0AVac/h ejwt - (V0 + Vacejwt0A (1/h2) dh/dt.

And that is as far as you can go without knowing what h(t) is.
Of course, replace each term with its real part to get the actual dependence of I on h.

Note that if dh/dt = 0 you get the standard relation between current and voltage of a fixed capacitor.
 
Last edited:
rude man said:
So why are you pursuing force on the plates? As I suspected, d is the independent variable. You already did a lot of analysis & came up with
I = jCVACωejωt + V*(ε0A/d2) * d(d)/dt

I suggest replacing d with h to avoid confusion.

So that's I = jCVacωejωt + V*(ε0A/h2) * dh/dt

Now, replacing C with ε0A/h and V with V0 + Vacejwt you get

I = jwε0A/h ejwt - (V0 + Vacejwt0A (1/h2) dh/dt.

And that is as far as you can go without knowing what h(t) is.
Of course, replace each term with its real part to get the actual dependence of I on h.

Note that if dh/dt = 0 you get the standard relation between current and voltage of a fixed capacitor.

So I thought. I'm not sure how he got it as linearly related to d; I'll have to look at his working when I go back to the lab and i'll post it here.
 
unscientific said:
So I thought. I'm not sure how he got it as linearly related to d; I'll have to look at his working when I go back to the lab and i'll post it here.

Thanks. Only thing I can think of is if dh/dt is small, but even then I goes as 1/h, not h.

I suspect we don't have the complete picture. Could you post the question as originally posed? Thanks for posting the answer also, wish more OP's would do that.
 

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