- #1
totalphysnoob
- 1
- 0
I was wondering for a series of capacitors connected together (after full charging), is there a voltage difference between the negative plate of one capacitor and the positive plate of another capacitor down the line?
-------+q||-q(a)-------+q(b)||-q------+q||-q----------
i.e. between points a and b
in my opinion, judging from the statement that for a series of capacitors the voltage of each individual capacitor add together to give the total voltage of the charging battery, it must be that from points a to b there is no potential difference change because whatever voltage drop occurred in the first capacitor would be canceled out at least partially as you move up in potential again, furthermore since two capacitors are connected by a wire if there still existed a potential difference between them then current would still exist and the situation wouldn't be equilbrium anymore
the problem is I can't reconcile the above with the fact that as you go from point a to point b you are going from an area of negative charge (and lower potential) to an area of positive charge (and higher potential), any help?
-------+q||-q(a)-------+q(b)||-q------+q||-q----------
i.e. between points a and b
in my opinion, judging from the statement that for a series of capacitors the voltage of each individual capacitor add together to give the total voltage of the charging battery, it must be that from points a to b there is no potential difference change because whatever voltage drop occurred in the first capacitor would be canceled out at least partially as you move up in potential again, furthermore since two capacitors are connected by a wire if there still existed a potential difference between them then current would still exist and the situation wouldn't be equilbrium anymore
the problem is I can't reconcile the above with the fact that as you go from point a to point b you are going from an area of negative charge (and lower potential) to an area of positive charge (and higher potential), any help?