Capacitors in Series and finding voltage

We've been studying capacitors in series in my physics class. I have a problem tonight and I know the answer, I just don't know how to get to it.

The problems is as follows:

Find the voltage V1 across the first capacitor.
Express your answer in terms of V.

 

The first step is finding that they all have the same charge. Then, I think, I would find the equivalent capacitance which is equal to 11/6 C. From there I don't know where I would get the voltage for each one.

 

ofcourse, c=q/v... So Ceq=Q/Veq...

 

Ok by the Veq I meant the total voltage... So what we have is that the total voltage is equal to V. The C equivalence is equal to 11/6 C. And that the charge on each capacitor is Q. Now from that information, I am still at a loss as to how to determine the voltage across the first capacitor.

The answer is 6/11 V according to the system my homework is in...

 

Ok, I see that I made the mistake there... It is 6/11 C. So we would then set that 6/11 C = Q(for each capacitor) / (Vtot).

So Q = 6 (Vtot) (C) / 11 for each capacitor.

Now that we have that, we could then find the voltage by knowing the q=v/c equation.

C = (6/11 C Vtot / 11)/V1
C V1 = 6/11 C Vtot
V1 = 6/11 Vtot

And that's the answer!!! Thank you for your help!!!
The problem that I had was knowing to get the charge for each capacitor and then work backwards...