Solving Car Banked Problem: Friction Force at 88 km/h

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The discussion focuses on calculating the friction force required for a 1300 kg car rounding a banked curve with a radius of 70 m at a speed of 88 km/h and an angle of 12°. The equations of motion are established as the sum of vertical forces (Fy) and horizontal forces (Fx), leading to a system of equations that includes the normal force (Fn) and frictional force (Ffr). The solution involves using substitution to isolate Ffr from the equations, which are derived from Newton's second law.

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A 1300 kg car rounds a curve of radius 70 m banked at an angle of 12°. If the car is traveling at 88 km/h, how much friction force is required?

ok so this is what i did so far but i got stuck.

the sum of Fy = mg - Fncos(angle) + Ffrsin(angle) = ma = 0
the sum of Fx = Fnsin(angle) + Ffrcos(angle) = ma = mv^2/r

i don't know how to get Ffr alone from here...help please!
 
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In your math courses this would have been called a system of equations. Your system here is 2 by 2 (2 equations, 2 unknowns). You can solve it by substitution. That is, solve for one of the variables in one of the equations, and then substitute the result into the second equation to eliminate one variable.
 
so are my two unknowns Ffr and a?
 
No, they are the frictional force and the normal force. You do know a.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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