Car crash: Can it be an elastic collision?

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Homework Help Overview

The discussion revolves around the nature of collisions, specifically whether a car crash can be classified as an elastic collision. Participants explore the definitions and characteristics of elastic and inelastic collisions in the context of a hypothetical scenario involving two cars with specified masses and velocities.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definitions of elastic and inelastic collisions, questioning the implications of kinetic energy conservation and the effects of physical damage during a collision. There is also an exploration of a specific problem involving calculations of post-collision velocities.

Discussion Status

Some participants have provided guidance on interpreting the problem, affirming the original poster's understanding of the collision types. Multiple interpretations of the collision scenario are being explored, particularly regarding the realistic outcomes of car crashes versus textbook examples.

Contextual Notes

Participants note that the problem involves hypothetical data that may not reflect real-world physics accurately, emphasizing the importance of focusing on the provided information for the sake of the exercise.

kikidoll
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If two cars are going towards each other, collide, and then are separated (have separate masses and separate velocities)... that is an elastic collision, correct?
 
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yup i think so, inelastic is when the objects hit and then stop dead
 
An elastic collision requires conservation of kinetic energy and momentum. If there is so much as a single dent caused by the collision some kinetic energy will have changed in for example heat. In reality car crashes are always inelastic.
 
There are two extremes.
Perfectly inelastic when the objects stop dead and there is a total conversion of K.E.
Perfectly elastic when there is zero loss of K.E.These collisions can happen with atomic scale objects such as gas molecules.
The collision referred to lies between the extremes but is more inelastic.
 
That's why I am confused... let me paraphrase the problem (I don't remember it verbatim- these numbers won't work but you'll get the idea):

Car 1 is 1.45kg and is going 4 m/s in the positive x direction. Car 2 is 0.65kg and is going -0.9 m/s. They collide, and after car 2 is going 2 m/s... find the new velocity of car 1.

There's where I got confused. I thought car crashes were inelastic, and momentum would be conserved by:
MiVi (car 1) + MiVi (car 2) = (Mcar1+car2)(Vf)

Since it gave a new velocity for car 2, I assumed it meant that they separated:
MiVi (car 1) + MiVi (car 2) = MfVf (car 1) + MfVf (car 2)

I plugged in the numbers and found car 1's new Vf.

Does that sound right to you?
 
correct
 
Your intuition is correct, you won't see two cars bounce off each other during a head on collision in real life. However with these kind of textbook problems it's important to just look at the data given regardless of how realistic it is. Your answer is correct.
 
Yeah, impossible to have elastic collision. Elastic collision = bad because KE is conserved and we would be bouncing back pretty fast!

That's why car manufacturers have crush zones to help reduce KE into other forms of energy including heat.
 
Cyosis said:
Your intuition is correct, you won't see two cars bounce off each other during a head on collision in real life. However with these kind of textbook problems it's important to just look at the data given regardless of how realistic it is. Your answer is correct.


Thank you.
 

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