Consider the problem of a car traveling along a banked turn. Sometimes roads have a "reversed" banking angle. That is the road is tilted "away" from the center of curvature of the road. The coefficient of static friction between the tires and the road is [tex]\mu[/tex]s=0.50, the radius of curvature is 15m, and the banking angle is 10 degrees. What is the max speed at which a car can safely navigate such a turn?
The Attempt at a Solution
I know the answer is supposed to be 7.2 m/s, however I keep getting in the whereabouts of 10m/s.
here is what I did: (0.5)(m)(9.81cos10-v2/15)=1.703(m)
divide out the m to cancel mass giving you:
divide out 0.5
subtract 9.8 cos10
multiply both sides by -15
take the square root of 93.662085
I don't know what I'm doing wrong, but from what I understand the normal force is reduced due to the reversed banking angle. Other than that I'm not real sure where I'm going wrong, I don't know if the equations I've figured out are not correct. I could really use some help, my homework is due on Wednesday and this is the only one I can't figure out. Thanks!!!