Car Passes Bus: Velocity Ques. Answered in 5 Secs

  • Thread starter Thread starter 1irishman
  • Start date Start date
  • Tags Tags
    Velocity
Click For Summary

Homework Help Overview

The problem involves a car and a bus traveling in the same direction, with specific lengths and velocities. The car accelerates for a certain duration, and the question is focused on determining the time it takes for the car to completely pass the bus.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the initial conditions, including the velocities and distances involved. There is an exploration of the car's acceleration and its effect on the time to pass the bus. Some participants question the clarity of the problem setup and the calculations regarding distances and velocities.

Discussion Status

There are multiple lines of reasoning being explored, with some participants confirming calculations while others express uncertainty. A few participants have provided guidance on the velocity calculations, and there is an ongoing examination of the time required for the car to pass the bus.

Contextual Notes

Participants note potential ambiguities in the problem statement, particularly regarding the reference points for the distances involved. There is also a focus on the assumptions made about the velocities and the effects of acceleration.

1irishman
Messages
243
Reaction score
0
1. Homework Statement
A car of length 4m and a bus of length 12m are traveling in the same direction 20m apart. The cars current velocity is 10m/s and the buses current velocity is 20m/s, the car suddenly starts to accelerate at 5m/s^2 and stops accelerating after 5 seconds. How long does it take the car to completely pass the bus?2. Homework Equations
d=Vit + 1/2at^2
i'm not sure about other ones that can be used here...3. The Attempt at a Solution
i figured (not sure if it's right though) the bus travels 100m in 5s and the car travels 112.5m in the same amount of time. So the original distance of 20m between the car and the bus has lessened to 20m - 12.5m = 7.5m. So the distance between the bus and the car is now 7.5m. Not sure how to proceed from here...hints? Thanks.
 
Last edited:
Physics news on Phys.org
What is the velocity of the car after 5 seconds?
Problem says that the car and bus are 20 m part. But it is not clear form which point to which point
 
The velocity of the car after 5 seconds is 10m/s (back to its original velocity).
 
1irishman said:
The velocity of the car after 5 seconds is 10m/s (back to its original velocity).
This is not correct. Use
v = vo + at
 
are my distances wrong then?
 
1irishman said:
are my distances wrong then?
They are correct.
 
Okay i have:
if vi of car=10m/s
a=5m/s^2
t=5s
then vf=35m/s
Is that right so far? thanks.
 
1irishman said:
Okay i have:
if vi of car=10m/s
a=5m/s^2
t=5s
then vf=35m/s
Is that right so far? thanks.
Yes. It is correct.
 
okay...i think I've solved it:
since cars new constant speed is 35m/s and distance is 23.5m.
The relative speed to the bus should be 15m/s.
So, v=15m/s
d=23.5m
then t=1.6s
So, it should take the car 6.6s to pass the bus right?
 
  • #10
1irishman said:
okay...i think I've solved it:
since cars new constant speed is 35m/s and distance is 23.5m.
The relative speed to the bus should be 15m/s.
So, v=15m/s
d=23.5m
then t=1.6s?
So, it should take the car 6.6s to pass the bus right?
v = d/t.
Then t = ?
 
  • #11
1.6s plus 5s
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K