1. The problem statement, all variables and given/known data A woman is running at a constant velocity of 5.0m/s in an attempt to catch a bus. When she is 11m from the bus, it pulls away with a constant acceleration of +1.0m/s2. From this point, how much time does it take her to reach the bus if she keeps running with the same velocity? 2. The attempt at a solution Finding the time d = di + vit+1/2at2 0 = 11 + 0t + 1/2(1)t2 0 = 11 + .5t2 t = sqrt of 11.5 t = 3.39 Distance traveled by woman d = v*t d = 5*3.39 d = 16.95m Distance traveled by bus vf = vi + at = 0+1*3.39 vf = 3.39 d = 1/2 (vi + vf)t d = 1/2 (3.39) 3.39 d = 1/2 * 11.5 d = 5.75 The bus traveled 5.75m, add in the initial distance of 11m 16.75m That's the closest I can get to the answer. Any guidance on where I want wrong? Thanks!