Car Suspension Homework: Find Speed to Avoid Wild Bouncing

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SUMMARY

The discussion focuses on calculating the speed at which a car should avoid driving over periodic dips to prevent excessive bouncing due to suspension dynamics. The car's suspension consists of four identical springs, each compressed by 10 cm to support a total mass of 1000 kg. The derived speed to avoid is 7 m/s, calculated using the formula v = sqrt(g * r), where g is the acceleration due to gravity and r is the radius of the dips. The conversation emphasizes the importance of understanding resonance conditions in suspension systems.

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Homework Statement


Assume your car’s suspension consists of 4 identical springs (one at each wheel). You notice that to support the mass of the car, each spring is compressed from its equilibrium length by 10 cm. The total “suspended” mass of your car is 1000 kg.
a) Determine the spring constant k of each of your suspension springs.
b) You drive with worn out shock absorbers over a roadway that has periodic small dips in it spaced 10 m apart (this can occur, for example, when the roadway is constructed by pouring concrete in uniform segments; the gaps between the smooth segments constitute such evenly spaced dips). What speed should you avoid, to prevent your car from bouncing wildly up and down?
(I already found a). Just need to do b), thanks)

Homework Equations


force downwards = mg = force radial = m*a (radial)


The Attempt at a Solution



So the car would not lift up when going over the bump so not to cause force upwards and making the car bounce
radius = r = 5 meters
force downwards = mg = force radial = m*a (radial)
mg = m*(v^2)/r
sqrt(g*r) = v
v = 7 m/s
 
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I'm not sure where you got the radius in your attempt at solving this - but I think you're a little confused. Maybe you should think about how you could avoid resonance occurring - or for that matter, what are the conditions that would cause resonance to occur.
 

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