Oscillations car suspension help

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Homework Help Overview

The problem involves a car's suspension system responding to vertical oscillations caused by an earthquake, with specific parameters regarding the mass of the car and its occupants. The goal is to determine how much the car's suspension lifts when the occupants exit.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of formulas related to oscillations and forces, questioning the setup of equations and the calculation of spring constant k. There is a focus on the relationship between the total mass and the resulting displacement of the car's body.

Discussion Status

Participants are actively engaging with the problem, sharing their calculations and questioning each other's approaches. There is a recognition of differing results, particularly regarding the value of k, indicating a productive exploration of the problem.

Contextual Notes

Some participants note potential discrepancies in calculations and the need to clarify the correct formulation of the equations used, particularly regarding the forces acting on the system.

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Homework Statement


Four people, each with a mass of 71.7 kg, are in a car with a mass of 1150 kg. An earthquake strikes. The driver manages to pull of the road and stop, as the vertical oscillations of the ground surface make the car bounce up and down on its suspension springs. When the frequency of the shaking is 1.60 Hz, the car exhibits a maximum amplitude of vibration. The earthquake ends and the four people leave the car as fast as they can. By what distance does the car's undamaged suspension lift the car's body as the people get out?


Homework Equations





The Attempt at a Solution



so i used (2pif)^2 = k/(M+m) m = the weight of all four men

so (M+m)g-mg = k(x2-x1)

which gives delta_x = Mg/[(M+m)(2pif)^2)]

and i got .0776 m

but this is wrong? any help please
 
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(M+m)g-mg = k(x2-x1)
Seems to me it should be (M+m)g-Mg = k(x2-x1)
since you want the difference between the car alone (M) and the car with people (M+m). Might be worth stopping to figure out k so we can compare answers at that point.
 


well k wouldn't it just be (2pif)^2(M+m)

so at the end we would get delta_x = mg/((M+m)(2pif)^2) = .016m ??
 


delta_x = mg/((M+m)(2pif)^2) = .016m ??
This is delta x = mg/k
Yes, looks good. But I don't get .016. What did you get for k?
Looks like we differ in the numbers entered or calculated.
 


for k i got 1.742 x 10^5

what did you get?
 

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