Chemistry Carbocations Stability: Compare 2 & 3 for Electron Induction

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The discussion centers on the stability of two carbocations, with the initial assessment incorrectly suggesting that molecule 2 is more stable due to its hydrogen atom lacking an inductive effect. However, it is clarified that tertiary carbocations, which have three carbon substituents, are generally more stable than secondary carbocations with only two carbon substituents and one hydrogen. The inductive effect of carbon atoms is electron-donating, enhancing stability compared to hydrogen. Thus, molecule 3, with more carbon atoms, is indeed the more stable option. The misunderstanding lies in the incorrect application of the inductive effect in evaluating carbocation stability.
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Homework Statement
Which carbocation is more stable
Relevant Equations
Inductive effect
Hi,
I have to determine which molecule ( 2 and 3) is more stable.
I tried to determine the stability using the inductive effect, but when I tried to that, I ended with molecule 2 being more stable than molecule 3 since:
x3 ch3 will push electrons towards c+
Whilst in the 2nd molecule the is a H, which have no inductive effect on C+ therefore it's more stable which is incorrect.
Please tell me where I misunderstood the problem thank you!
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Generally, tertiary carbocations are more stable than secondary carbocations. So you're definitely right that compound 2 being more stable is incorrect. Carbon is electron donating compared to hydrogen. So a carbocation placed next to three carbon atoms will be more stable than one placed next to two carbon atoms and one hydrogen with that reasoning.
 
Mayhem said:
Generally, tertiary carbocations are more stable than secondary carbocations. So you're definitely right that compound 2 being more stable is incorrect. Carbon is electron donating compared to hydrogen. So a carbocation placed next to three carbon atoms will be more stable than one placed next to two carbon atoms and one hydrogen with that reasoning.
Thank you for your reply sir!
 
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