Carnot Cycle with negative temperatures

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SUMMARY

The discussion centers on the Carnot cycle applied to heat engines operating at negative temperatures. It establishes that energy must be extracted from the reservoir with a lower magnitude of negative temperature to achieve a positive net work output. The efficiency of such an engine is defined using the equation η = (T_hot - T_cold)/T_hot, but complications arise due to the nature of negative temperatures, which defy conventional thermodynamic principles. The maximum efficiency achievable without the reversibility constraint remains a topic of debate, as negative temperatures introduce unique behaviors in thermodynamic systems.

PREREQUISITES
  • Understanding of the Carnot cycle and its principles
  • Familiarity with thermodynamic concepts of heat and entropy
  • Knowledge of the equations ΔS = Q/T and η = (T_hot - T_cold)/T_hot
  • Basic grasp of negative temperature phenomena in thermodynamics
NEXT STEPS
  • Research the implications of negative temperatures in thermodynamics
  • Study the derivation and applications of the Carnot efficiency equation
  • Explore the concept of entropy generation in irreversible processes
  • Investigate specific systems that can achieve negative temperatures
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Students and professionals in thermodynamics, physicists exploring advanced heat engine concepts, and engineers designing systems that operate under unconventional thermal conditions.

Thomas Brady
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Homework Statement


Heat engines at negative temperatures. Consider using two heat reservoirs to run an engine (analogous to the Carnot cycle of chapter 3), but specify that both temperatures, T_hot and T_cold, are negative temperatures. The engine is to run reversibly.
(a) If the engine is to do a positive net amount of work, from which reservoir must the energy be extracted?

(b) Under the same conditions, what is the engine’s efficiency?

(c) If you drop the requirment of reversibility, what is the maximum efficiency and how would you achieve it?

Homework Equations


ΔS = Q/T

η = W_in/Q_out = (T_hot - T_cold)/T_hot

The Attempt at a Solution


So for (a) I'm pretty sure the reservoir with a lower magnitude negative temperature is the one from which energy must be extracted by how negative temperatures work to my knowledge. I'm not sure what this means for the efficiency. If T_hot is the temperature from which energy is extracted then the typical expression for max efficiency would have a negative result which I don't think is right. Do I need to get a different expression for efficiency? Also wouldn't the maximum efficiency achievable for part (c) still be the same as the efficiency of the reversible engine? Thanks for the help.

P.S. Sorry I am a novice and am having trouble with subscript
 
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What does entropy balance tell you if the system is reversible? If it's irreversible? Remember that you have heat enter/exiting the system at two reservoirs at different temperatures, and that the full equation for entropy balance is ##\Delta S = \sum \frac{Q}{T} + \sigma##, where ##\sigma## is how much entropy is generated by irreversibilities. Use that information and solve for the efficiency as a function of ##\sigma##.

Thomas Brady said:
Also wouldn't the maximum efficiency achievable for part (c) still be the same as the efficiency of the reversible engine?

Nope! Negative temperatures do weird things, as you'll see.
 
No such thing as negative K temperatures so I wouldn't pursue it.
 
rude man said:
No such thing as negative K temperatures so I wouldn't pursue it.
Uh Oh... duck
 
rude man said:
No such thing as negative K temperatures so I wouldn't pursue it.
What do you mean?
 
DrClaude said:
What do you mean?
I mean tthat after you get to zero K, which is absolute zero, you just don't want to get any colder!
 
TSny said:
Uh Oh... duck
Did I get another one wrong: :smile:
 
rude man said:
I mean tthat after you get to zero K, which is absolute zero, you just don't want to get any colder!
That's true in the sense that if you could extract enough energy to get a system to 0 K, you cannot extract more heat and get to negative temperatures.

But there are special systems for which you can imagine adding a finite amount of heat until the temperature becomes infinite, and then add even more energy to get to negative temperatures! Thus, negative temperatures are "hotter" than any positive temperature.

This craziness is a result of the way temperature is defined in thermodynamics in terms of heat and entropy. Before I say too much that is wrong, I will refer you to https://en.wikipedia.org/wiki/Negative_temperature.
 
TSny said:
That's true in the sense that if you could extract enough energy to get a system to 0 K, you cannot extract more heat and get to negative temperatures.

But there are special systems for which you can imagine adding a finite amount of heat until the temperature becomes infinite, and then add even more energy to get to negative temperatures! Thus, negative temperatures are "hotter" than any positive temperature.

This craziness is a result of the way temperature is defined in thermodynamics in terms of heat and entropy. Before I say too much that is wrong, I will refer you to https://en.wikipedia.org/wiki/Negative_temperature.
One lives and one learns ...
What goes around, comes around?

:smile:
 
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