Carnot engine boiling water problem

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The problem involves a Carnot engine using boiling water as a hot reservoir and ice water as a cold reservoir, with 5650 J of heat input. The user calculated the efficiency using the formula 1 - (Ql/Qh) and found the work done to be 1514.75 J. However, the conversion to kilograms of ice melted using the latent heat of fusion (Lf) resulted in an incorrect answer of 0.0045 kg. The user seeks assistance in resolving the calculation error to determine the correct mass of ice melted. Clarification on the proper application of the Carnot efficiency and heat transfer principles is needed.
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Homework Statement


A Carnot engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a large tub of ice and water. When 5650 J of heat is put into the engine and the engine produces work, how many kilograms of ice in the tub are melted due to the heat delivered to the cold reservoir?

Homework Equations



Melting point of water: 0C
Boiling point of water: 100C
Lf water: 33.5x10^4
Lv water: 22.6x10^5
1-(Ql/Qh)


The Attempt at a Solution



I found 1-Ql/Qh to be 1-(273/373) = 0.268 and then i multiplied that by 5650J and got 1514.75J to be the work done
Then I converted that using the Lf to get the kg so (1514.75J)/(33.5x10^4J/kg) = 0.0045kg
 
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