Car's coefficent of kinetic friction help

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SUMMARY

The discussion centers on calculating the coefficient of kinetic friction (uk) for a car weighing 1500 kg traveling at a constant speed of 20 m/s on a wet asphalt road. The initial incorrect calculation of uk as 1.2 and a stopping distance of 60 m was corrected to uk = 0.53 and a stopping distance of 38.2 m. This correction highlights the importance of accurate data and calculations in physics problems involving friction and motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of friction and its coefficients
  • Familiarity with kinematic equations
  • Ability to perform calculations involving mass, speed, and distance
NEXT STEPS
  • Study the derivation of the coefficient of kinetic friction using real-world examples
  • Learn how to apply kinematic equations to solve motion problems
  • Explore the effects of different road surfaces on friction coefficients
  • Investigate the role of vehicle weight and speed in stopping distances
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding vehicle dynamics and safety measures related to braking on slippery surfaces.

pharaoh
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you are driving a 1500 kg car at a constant speed of 20 m/s along Grand Blvd. a wet road, asphalt level road. as you approach the intersection, you get a call on your cell phone. then you forgot about the stop sign. when you see the stop sign you slam on the brakes 20 meter from the intersection. the car's wheel lock, the tire begin skidding and the car slides to a halt. what was your coefficient of kinetic friction (uk) and how far did you ge before stopping?

i got uk= 1.2 and d= 60 m but i am not sure
 
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pharaoh said:
i got uk= 1.2 and d= 60 m but i am not sure
Those two numbers are not consisteent with one another. Where did you get uk? Did you look it up in a table?
 
thanks for replying but i found the answer
uk= 0.53 and the d= 38.2
 

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