Cathode Rays & Velocity: Uniform or Accelerated?

Click For Summary
SUMMARY

The discussion centers on the behavior of cathode rays, specifically the velocity of electrons emitted from a cathode in a discharge tube experiment. It is established that electrons are accelerated by the external electric field created by the applied potential difference (V). The velocity of the electrons can be calculated using the formula v = sqrt(2 * p.d. * e / m), where e represents the charge of the electron and m its mass. The confusion arises from the distinction between initial velocity and the accelerated velocity due to the electric field.

PREREQUISITES
  • Understanding of cathode ray tube (CRT) principles
  • Familiarity with electric fields and potential difference
  • Knowledge of basic physics formulas, particularly kinetic energy equations
  • Concept of charged particles and their behavior in electric fields
NEXT STEPS
  • Study the principles of electric fields and their effects on charged particles
  • Learn about the kinetic energy of electrons in electric fields
  • Explore the derivation and application of the formula v = sqrt(2 * p.d. * e / m)
  • Investigate the differences between uniform and accelerated motion in physics
USEFUL FOR

Physics students, educators, and anyone interested in the dynamics of charged particles in electric fields, particularly in the context of cathode ray experiments.

mysteriously
Messages
12
Reaction score
0
During discharge tube experiment, the cathode rays are emitted from cathode at very low pressure...it is said that these rays move at very high velocity(if we apply high Potential Difference between 2 electrodes)...do these rays( stream of electrons) travel in uniform velocity or aren't they accelerated due to presence of external electric field?why do we directly find out the velocity of electron by the formula v=sq.rt(2*p.d.*e/m) ? i am confused whether the velocity of electrons is uniform or it is being accelerated by the external electric field??
 
Physics news on Phys.org
mysteriously said:
During discharge tube experiment, the cathode rays are emitted from cathode at very low pressure...it is said that these rays move at very high velocity(if we apply high Potential Difference between 2 electrodes)...do these rays( stream of electrons) travel in uniform velocity or aren't they accelerated due to presence of external electric field?why do we directly find out the velocity of electron by the formula v=sq.rt(2*p.d.*e/m) ? i am confused whether the velocity of electrons is uniform or it is being accelerated by the external electric field??

While the electrons are emitted with some velocity, the overwhelming majority of the energy/speed picked up by the electrons are from the applied field. Remember, these are electrons! They are charged particles. Charged particles can interact with an external electric field. So you apply such a field to cause them to speed up.

If you apply a potential difference of V, then the energy gained by the electrons is eV = 1/2 mv^2 (assuming non-relativistic). So calculate your speed from there (assuming it started with 0 or negligible speed, which is a valid assumption in most cases).

P.S. This is not a "Quantum Physics" topic and has been moved out of that forum.

Zz.
 
dont they accelerate in the electric field?every charged particle in electric field is accelerated...then what and at what time is the velocity we calculate from above formula??
 
mysteriously said:
dont they accelerate in the electric field?every charged particle in electric field is accelerated...then what and at what time is the velocity we calculate from above formula??
You have a tube with a cathode at one end. Where is the anode?
 
mysteriously said:
dont they accelerate in the electric field?every charged particle in electric field is accelerated...then what and at what time is the velocity we calculate from above formula??

This is utterly puzzling. What did you think I meant when I said that these charge particles interact with electric field?

And why can't you just calculate the velocity? I've given you everything you need already!

Zz.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 15 ·
Replies
15
Views
5K
Replies
0
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 28 ·
Replies
28
Views
5K