Graduate Cauchy’s integral theorem and residue theorem, what’s the difference

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Cauchy’s integral theorem is applicable for evaluating integrals over closed contours when the function is analytic inside the contour, while the residue theorem is used for functions with singularities, allowing for the calculation of integrals around poles. The residue theorem is particularly advantageous when dealing with multiple poles, as it simplifies calculations significantly. For the integral of 1/z, both theorems can be applied, but the residue theorem is often preferred for its ease of computation. Understanding the conditions for each theorem is crucial; Cauchy’s requires analyticity, whereas the residue theorem requires identification of poles and their residues. Mastery of these concepts enhances proficiency in complex analysis.
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when to use residue theorem and when to use Cauchy’s integral theorem?
May I ask when we should use Cauchy’s integral theorem and when to use residue theorem? It seems for integral 1/z, we can use both of them. What are the conditions for each of them?
Thanks in advance!
 
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There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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