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## Homework Statement

Let f(x)= 2x , 0<x<1 , zero elsewhere, be the pdf of X.

Compute the cdf of Y=1/X

## Homework Equations

cdf of X = p(X< x)

## The Attempt at a Solution

P(1/X <= y)

= P(X <= 1/y)

int 2x from 0 to 1/y

= x^2 eval from 0 to 1/y

= 1/y^2

so the cdf is 1/y^2 for 1<y<infinty

however i don't think this is right.... the text book answers state the cdf as 1-1/y^2

so im confused. thanks for any help!