Cell and membrane volume physics

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SUMMARY

The discussion centers on calculating the volume of a human cell and its membrane, modeled as a sphere. The volume of the cell, with a diameter of 10 μm, is correctly calculated as 523.60 μm³ using the formula V = 4/3*pi*r³. However, the volume of the cell membrane was incorrectly approached by using the membrane thickness as the radius. The correct method involves calculating the volume of a spherical shell, taking into account the outer radius of 5 μm and the thickness of 4.2 nm.

PREREQUISITES
  • Understanding of spherical volume calculations
  • Familiarity with unit conversions, specifically between nanometers and micrometers
  • Knowledge of the concept of a spherical shell
  • Basic proficiency in geometry and algebra
NEXT STEPS
  • Learn how to calculate the volume of a spherical shell
  • Study unit conversion techniques between different metric units
  • Explore applications of volume calculations in biological contexts
  • Review geometric modeling of biological structures
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Students in biology or physics, educators teaching cell biology, and anyone interested in mathematical modeling of biological structures.

Akewal
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Homework Statement


A typical human cell is approximately 10 μm in diameter and enclosed by a membrane that is 4.2 nm thick. To simplify the calculations, model the cell as a sphere.
1) What is the volume of cell? (in μm^3)
2) What is the volume of cell membrane? (in μm^3)
3) Percent cell volume the membrane occupies

Homework Equations


V= 4/3*pi*r^3

The Attempt at a Solution


I knew the volume of sphere, so I could easily solve for number 1 Because 10 was the diameter, I divided it by 2 which gave me a radius of 5.
1) 4/3*pi*125= 523.60μm^3
2) This is where I got stuck. I converted 4.2 nm to μm (multiplying 4.2 with 0.001), and used the volume formula, with .0042 μm as my r. The answer is wrong!

What I am doing wrong?
 
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Hello Akewal, ##\qquad##:welcome:##\qquad##!

The way you describe it, you calculated the volume of a sphere with a radius of 4.2 nm ...

If you make a coarse sketch, you see that you are after the volume of a shell with radius 5 ##\mu##m and a thickness of 4.2 nm ... A different beast !
 

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